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2 years ago

5

An object travels 50 m in 4 s. It had no initial velocity and experiences constant acceleration. What is the magnitude of the ac

celeration?

1 answer:

Allisa [31]2 years ago

3 0

Answer:

The formula to calculate velocity in this case:

v = v0 + at

=> a = (v - v0)/t

= (50 - 0)/4

= 50/4 = 12.5 (m/s2)

Hope this helps!

:)

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Tom’s company has been contracted to excavate uranium ore with minimal ground disruption. What process should his company use?

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Evaluate the final kinetic energy of the supply spacecraft for the actual tractor beam force, F(x)=αx3+βF(x)=αx3+β.

Elan Coil [88]

Answer:

K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

Explanation:

To find the variation of kinetic energy, let's use the work energy theorem

W = ΔK

∫ F .dx = K -K₀

If the body starts from rest K₀ = 0

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we substitute and integrate

α ∫ x³ dx + β ∫ dx = K

α x⁴ / 4 + β x / 1 = K

we evaluate from the lower limit F = 0 to the upper limit F

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K = αX⁴ / 4 + β x

K = 1.525 10⁻⁹ x⁴ + 4.1 10⁶ x

in order to finish the calculation we must know the displacement

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2 years ago

What two processes practiced by scientists increase the likelihood of a successful outcome in science?

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Answer:

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A 5 kg block moves with a constant speed of 10 ms to the right on a smooth surface where frictional forces are considered to be

nirvana33 [79]

Answer:

Work done, W = 19.6 J

Explanation:

It is given that,

Mass of the block, m = 5 kg

Speed of the block, v = 10 m/s

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Distance covered by the block, d = 2 m

As the block passes through the rough part, some of the energy gets lost and this energy is equal to the work done by the kinetic energy.

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A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/

larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

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Speed of the first piece, $v_1=82\ m/s$ (along x axis)

Speed of the second piece, $v_2=45\ m/s$ (along y axis)

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The total momentum of the two pieces.

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Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

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