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Semmy [17]
2 years ago
14

A transverse wave is traveling from north to south. Which statement could be true for the motion of the wave particles in the me

dium? Their direction of motion is east and west. Their direction of motion is north and east. Their direction of motion is south and north. Their direction of motion is north and west. Their direction of motion is south and east.
Physics
2 answers:
Nastasia [14]2 years ago
8 0

Answer : The correct option is, Their direction of motion is east and west.

Explanation :

There are two types of waves :

Longitudinal waves : It is defined as the waves in which the particles of the medium move in the direction of the wave.

Transverse wave : It is defined as the waves in which the particles of the medium travel perpendicularly to the direction of the wave.

When a transverse wave is traveling from north to south then the direction of  motion of the wave particle will be perpendicular to north-south direction which is east-west direction.

Hence, the correct option is, Their direction of motion is east and west.

Vikki [24]2 years ago
3 0
Transverse waves travel on a direction that is perpendicular to the motion of the particles (or whatever medium is waving)  So the particles must be moving east to west, which is transverse to the north-south motion of the wave
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Hippos spend much of their lives in water, but amazingly, they don’t swim. manatees, They have, like little very body fat. The d
kenny6666 [7]

Answer:

428.59 N

Explanation:

Buoyant force, B=Vg\rho where V is volume, g is gravitational constant and \rho is density

B+F_{upward}=mg where F_{upward} is upward force

Vg\rho_{w}+F_{upward}=mg

F_{upward}=mg- Vg\rho_{w}

F_{upward}=g(mg- V\rho_{w})=g(m-m\frac {\rho_{w}{\rho_{hippo}} where \rho_{hippo} is the density of hippo

F_{upward}=mg(1-\frac {\rho_{w}}{\rho_{hippo}})

Using g as 9.81

F_{upward}=1500*9.81*(1-1000/1030)= 428.5922 N

Therefore, the upward force=428.59 N

3 0
2 years ago
In the Atwood machine shown below, m1 = 2.00 kg and m2 = 6.05 kg. The masses of the pulley and string are negligible by comparis
Rus_ich [418]
M1 descending
−m1g + T = m1a 

m2 ascending
m2g − T = m2a

this gives :
(m2 − m1)g = (m1 + m2)a 

a = (m2 − m1)g/m1 + m2
   = (5.60 − 2)/(2 + 5.60) x 9.81 
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5 0
2 years ago
If a single constant force acts on an object that moves on a straight line, the object's velocity is a linear function of time.
olya-2409 [2.1K]

Answer:

F=mkv

Explanation:

Given that

v = v_i - kx

We know that acceleration a given as

a=\dfrac{dv}{dt}

v = v_i - kx

\dfrac{dv}{dt}=\dfrac{dv_i}{dt}-k\dfrac{dx}{dt}

\dfrac{dv}{dt}=0-k\dfrac{dx}{dt}

We know that

F=m\dfrac{dv}{dt}

F=-mk\dfrac{dx}{dt}

F=-mkv

So the magnitude of force F

F=mkv

5 0
2 years ago
Determine the sign (+ or −) of the torque about the elbow caused by the biceps, τbiceps, the sign of the weight of the forearm,
Alex Ar [27]
Ans: 
1.  τbiceps = +(Positive)
2.  τforearm = -(Negative)
3.  τball = -(Negative)

Explanation:

The figure is attached down below.

1. T<span>orque about the elbow caused by the biceps, τbiceps:
Since Torque = r x F (where r and F are the vectors)
</span>Where r is the vector from elbow to the biceps.
<span>
We can see in the figure that F(biceps) is in upward direction, and by applying the right hand rule from r to F, we get the counterclockwise direction. The torque in counterclockwise direction is positive(+). Therefore, the sign would be +.

2. </span>Torque about the the weight of the forearm, τforearm:
Since Torque = r x F (where r and F are the vectors)
Where r is the vector from elbow to the forearm.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(forearm) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

3. Torque about the the weight of the ball, τball:
Since Torque = r x F (where r and F are the vectors)
Where r is the vector from elbow to the ball.

Also weight is the special kind of Force caused by the gravity.

We can see in the figure that W(ball) is in downward direction, and by applying the right hand rule from r to F, we get the clockwise direction. The torque in clockwise direction is negative(-). Therefore, the sign would be -.

8 0
2 years ago
Which of the following sketches represents a possible configuration for this problem?
garri49 [273]
Where are the following sketches?
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