Apple hits the surface with speed 16.2 m/s
The angle made by the apple velocity with normal to the incline surface is given as 20 degree
now the component of velocity which is parallel to the surface and perpendicular to the surface is given as
so here we have
<em>so its velocity along the incline plane will be 5.5 m/s</em>
Answer:
a) Velocity = 4.2m/s
b) Acceleration = 2.94m/s^2
c) Force exerted on the floor= 1401.4×10^3N
Explanation:
a) Velocity,V=sqrt(2×9.8×0.900)
V= 4.2m/s
b) Vf2= V^2+2ay2
a= 4.2^2 - 0/2×3
a= 17.64/6= 2.94m/s^2
c) Newton's 2nd law indicates:
Fnet= F - mg=ma
F= m(g+a)
F=110(9.8+2.94)
F=110×12.94
F= 1401.4N
Answer: 8.1 x 10^24
Explanation:
I(t) = (0.6 A) e^(-t/6 hr)
I'll leave out units for neatness: I(t) = 0.6e^(-t/6)
If t is in seconds then since 1hr = 3600s: I(t) = 0.6e^(-t/(6 x 3600) ).
For neatness let k = 1/(6x3600) = 4.63x10^-5, then:
I(t) = 0.6e^(-kt)
Providing t is in seconds, total charge Q in coulombs is
Q= ∫ I(t).dt evaluated from t=0 to t=∞.
Q = ∫(0.6e^(-kt)
= (0.6/-k)e^(-kt) evaluated from t=0 to t=∞.
= -(0.6/k)[e^-∞ - e^-0]
= -0.6/k[0 - 1]
= 0.6/k
= 0.6/(4.63x10^-5)
= 12958 C
Since the magnitude of the charge on an electron = 1.6x10⁻¹⁹ C, the number of electrons is 12958/(1.6x10^-19) = 8.1x10^24 to two significant figures.
Prior to touching the bar magnet, the magnetic domains in the nail were pointing in random directions. When Taylor touched the nail to the bar magnet the magnetic fields of the magnetic domains aligned and it became a temporary magnet.
