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Ksenya-84 [330]
1 year ago
10

Taylor places a nail on a bar magnet. The nail sticks to the magnet when lifted up off the table. She touches a paperclip to the

nail and it sticks to the nail. Explain what happened to the magnetic domains of the nail before and after touching it to the bar magnet.
Physics
2 answers:
diamong [38]1 year ago
8 0

Taylor places a nail on a bar magnet. The nail sticks to the magnet when lifted up off the table. She touches a paperclip to the nail and it sticks to the nail. Explain what happened to the magnetic domains of the nail before and after touching it to the bar magnet.

Ratling [72]1 year ago
5 0
Prior to touching the bar magnet, the magnetic domains in the nail were pointing in random directions. When Taylor touched the nail to the bar magnet the magnetic fields of the magnetic domains aligned and it became a temporary magnet.
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A cord is wrapped around the rim of a solid uniform wheel 0.280m in radius and of mass 8.80kg. A steady horizontal pull of 32N t
Grace [21]

Answer:25.97 rad/s^2

Explanation:

Given

radius of wheel r=0.28 m

mass of wheel m=8.80 kg

Force F=32 N

Moment of Inertia of solid wheel I=\frac{mr^2}{2}

I=\frac{8.8\times 0.28^2}{2}

I=0.344 kg-m^2

Torque is given by

\tau =F\times r=I\times \alpha

32\times 0.28=0.344\times \alpha

\alpha =25.97 rad/s^2

Force on the axle is 32 N since there is no linear acceleration of the system

using Third law F=32 N

Torque of the axle applied to the wheel is zero because force of axle imparted at the center of axle

3 0
2 years ago
A light ray strikes a plane mirror at an angle of 23° to the normal. What is the angle between the reflected ray and the mirror?
tiny-mole [99]

Answer:67^{\circ}

Explanation:

Given

Ray of light incident on plane making an angle of 23^{\circ} with normal

Thus incident angle i=23^{\circ}

So according to the law of incidence is equal to angle of reflection

\angle i=\angle r

thus \angle r=23^{\circ}

and angle between mirror and reflected ray =90^{\circ}-23^{\circ}

=67^{\circ}

4 0
2 years ago
A coat rack weighs 65.0 lbs when it is filled with winter coats and 40.0 lbs when it is empty. The base of the coat rack has an
Whitepunk [10]

Answer:

0.056 psi more pressure is exerted by filled coat rack than an empty coat rack.

Explanation:

First we find the pressure exerted by the rack without coat. So, for that purpose, we use formula:

P₁ = F/A

where,

P₁ = Pressure exerted by empty rack = ?

F = Force exerted by empty rack = Weight of Empty Rack = 40 lb

A = Base Area = 452.4 in²

Therefore,

P₁ = 40 lb/452.4 in²

P₁ = 0.088 psi

Now, we calculate the pressure exerted by the rack along with the coat.

P₂ = F/A

where,

P₂ = Pressure exerted by rack filled with coats= ?

F = Force exerted by filled rack = Weight of Filled Rack = 65 lb

A = Base Area = 452.4 in²

Therefore,

P₂ = 65 lb/452.4 in²

P₂ = 0.144 psi

Now, the difference between both pressures is:

ΔP = P₂ - P₁

ΔP = 0.144 psi - 0.088 psi

<u>ΔP = 0.056 psi</u>

8 0
2 years ago
A 4.00-kg box sits atop a 10.0-kg box on a horizontal table. The coefficient of kinetic friction between the two boxes and betwe
natta225 [31]
First, we have to calculate the normal forces on different surfaces.The normal force on the 4.00 kg, N1 = (4)(9.8) = 39.2 N. The normal force on the 10.0 kg, N2 = (14)(9.8) = 137.2 N. Looking at the 10.0 kg block, the static forces that counteract the pulling force equals the sum of the friction from the two surfaces. Fc = N1 * 0.80 + N2 * 0.80 = 141.12 N. Since the counter force is less than the pulling force, the blocks start to move and hence, kinetic frictions are considered.


Therefore, f1 = uk * N1 = (0.60)(39.2) = 23.52 N.
4 0
2 years ago
What boolean operation does the circuit compute?
vagabundo [1.1K]

A circuit computes various types of Boolean operations. As in the question no specific circuit has been shown,so we have to know the fundamental logic operations.

Out of the various types of logic operations in Boolean algebra,the simple operations are- addition,subtractions,multiplications,division through logic gates.

Various logic or Boolean operations are  NOT GATE,OR GATE ,AND GATE .

There are other operations also like NAND GATE,NOR GATE and XOR GATE etc

NOT gate is the simple logic gate which inverts one quantity.it makes 1[high] to 0[low] and vice versa.

OR gate gives 1 [high] when one of the input is 1 and low when all the inputs are low.

AND operation gives 1 when all the inputs are high and low when one of the input is low

NAND operation is AND gate followed by a NOT gate

NOR operation is the OR gate followed by a NOT gate.

Remembering these simple rules we can get the idea of the operations involved in the circuit. Each circuit has different symbols and gives different results.

8 0
2 years ago
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