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wolverine [178]
2 years ago
7

On the planet Abby, there is an homozygous lethal condition known as Gumball. Individuals with this condition chew gum till thei

r jaws hurt. A study of 1000 heterozygote Abbers (Gg) shows that 600 show the Gumball phenotype. Homozygous wild-type (gg) Abbers never show the phenotype. If we cross of a wild-type gg male with an affected female, what is the probability that an arbitrarily selected F1 will be wild-type?
A. 0.6
B. 0.0
C. 1.00
D. 0.70
E. 0.3
Physics
1 answer:
Ipatiy [6.2K]2 years ago
6 0

Answer:

D. 0.7 would be wild-type healthy

E. 0.3 would be affected Gg

Explanation:

Using the Punnett square we cross an homozygous male (gg), that is always healthy vs an heterozygous female (Gg). The result is 2 gg individuals, and 2 Gg individuals. Both gg individuals are healthy.

In a population of 1000 Gg individuals, 600 show the Gumball phenotype (unhealthy). It means that from the two heterozygous Gg (from the Punnett square), 1.2 show the unhealthy phenotype.

Again, from the Punnett square we have 4 individuals, that represent the 100%. 1.2 are unhealthy Gg, and represent 30% in F1.

This 30%, is equivalent to 0.3, that is the option E.

100 - 30 % = 70 %.  This is 0.7 for healthy wild-type, option D.

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Answer:

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Explanation:

The moment of parallel pipe rotating about it's axis is given by the formula;

I = \frac{M}{3} (a^{2} +b^{2} )   ---------------------------------1

(a) The kinetic energy of a parallel pipe is also given as;

k =\frac{1}{2} Iw^{2} --------------------------------2

Putting equation 1 into equation 2, we have;

k = \frac{M}{6} (a^{2} +b^{2} )w^{2}

k = \frac{Mw^{2} }{6} (a^{2} +b^{2} )

(b) The angular momentum is given by the formula;

τ = Iw -----------------------3

Putting equation 1 into equation 3, we have

τ = \frac{Mw}{3} (a^{2} +b^{2} )

But

τ = dτ/dt = \frac{M}{3} (a^{2} +b^{2} )\frac{dw}{dt}   ------------------4

where

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Equation 4 becomes;

τ = \frac{M}{3} (a^{2} +b^{2} ) ∝

8 0
2 years ago
A thermally isolated system is made up of a hot piece of aluminum and a cold piece of copper; the aluminum and the copper are in
blsea [12.9K]

Answer:

b) It is impossible to tell without knowing the masses.

Explanation:

The temperature change of a substance when it receives/gives off a certain amount of heat Q is given by

\Delta T= \frac{Q}{m C_s}

where

Q is the amount of heat

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In this case, we have a hot piece of aluminum in contact with a cold piece of copper: the amount of heat given off by the aluminum is equal to the amount of heat absorbed by the copper, so Q is the same for the two substances. However, we see that the temperature change of the two substances depends on two other factors: the mass, m, and the specific heat, Cs. So, since we know only the specific heat of the two substances, but not their mass, we can't tell which object will experience the greater temperature change.

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2 years ago
A toy rocket launcher can project a toy rocket at a speed as high as 35.0 m/s.
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Answer:

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8 0
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solution

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8 0
2 years ago
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