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IgorC [24]
1 year ago
7

Boat A and Boat B have the same mass. Boat A's velocity is three times greater than that of Boat B. Compared to

Physics
1 answer:
Sonbull [250]1 year ago
5 0

Answer: Nine times as much

Explanation:

The kinetic energy of an object is given by the following equation:

K=\frac{1}{2}mV^{2} (1)

Where:

K is the kinetic energy

m is the mass of the object

V is the velocity of the object

Now, in this case we have two boats, A and B, which have the same mass m. However, the velocity of boat A V_{A} is three times greater than that of Boat B V_{B}:

V_{A}=3V_{B} (2)

With this in mind, let's write the kinetic energy for each boat:

<u>Boat A:</u>

K_{A}=\frac{1}{2}mV_{A}^{2} (3)

Substituting (2) in (3):

K_{A}=\frac{1}{2}m(3V_{B})^{2} (4)

K_{A}=9(\frac{1}{2}mV_{B}^{2}) (5)

<u></u>

<u>Boat B:</u>

K_{B}=\frac{1}{2}mV_{B}^{2} (6)

Comparing (5) and (6) we can see the kinetic energy of boat A is nine times as much as the kinetic energy of boat B.

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Two people are talking at a distance of 3.0 m from where you are and you measure the sound intensity as 1.1 × 10-7 W/m2. Another
ioda

Answer:

6.1875\times 10^{-8}

Explanation:

Assuming uniform spread of sound with no significant reflections or absorption. We know that sound intensity varies I=\frac {k}{r^{2}} where r is the distance

Since intensity is given then when at 3 m

1.1\times 10^{-7}= \frac {k}{3^{2}}

k=3^{2}\times 1.1\times 10^{-7}= 9.9\times 10^{-7}

Since we have the constant then at 4m

Intensity, I= \frac {9.9\times 10^{-7}}{4^{2}}=6.1875\times 10^{-8}

8 0
1 year ago
A sprinter accelerates from rest to a velocity of 12m/s in the first 6 seconds of the 100 meter dash .
GREYUIT [131]

Answer:

a) 36 m

b) 64 m

Explanation:

Given:

v₀ = 0 m/2

v = 12 m/s

t = 6 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (12 m/s + 0 m/s) (6 s)

Δx = 36 m

The track is 100 m, so the sprinter still has to run another 64 m.

5 0
2 years ago
Now assume that the boat is subject to a drag force fd due to water resistance. is the component of the total momentum of the sy
DochEvi [55]
Based on the given details with this question, I can say that the direction of motion is not conserved. This is because the boat is subjected to an external force because of water resistance. So, the answer for this question would be NO.
4 0
1 year ago
Read 2 more answers
It's a snowy day and you're pulling a friend along a level road on a sled. You've both been taking physics, so she asks what you
Juli2301 [7.4K]

Answer:

0.0984

Explanation:

From the first diagram attached below; a free flow diagram shows the interpretation of this question which will be used  to solve this question.

From the diagram, the horizontal component of the force is:

F_X = F_{cos \ \theta}

Replacing 42°  for θ and 87.0° for F

F_X =87.0 \ N \ *cos \ 42 ^\circ

F_X =64.65 \ N

On the other hand, the vertical component  is ;

F_Y = Fsin \ \theta

Replacing 42°  for θ and 87.0° for F

F_Y =87.0 \ N \ *sin \ 42 ^\circ

F_Y =58.21  \ N

However, resolving the vector, let A be the be the component of the mutually perpendicular directions.

The magnitude of the two components is shown in the second attached diagram below and is now be written as A cos θ and A sin θ

The expression for the frictional force is expressed as follows:

f = \mu \ N

Where;

\mu is said to be the coefficient of the friction

N = the  normal force

Similarly the normal reaction (N) = mg - F sin θ

Replacing F_Y \ for \ F_{sin \  \theta}. The normal reaction can now be:

N = mg \ - \ F_Y

By balancing the forces, the horizontal component of the force equals to frictional force.

The horizontal component of the force is given as follows:

F_X = \mu \ ( mg - \ F_Y)

Making \mu the subject of the formular in the above equation; we have the following:

\mu \ = \ \frac{F_X}{mg - F_Y}

Replacing the following values: i.e

F_X \ = \ 64.65 \  N

m = 73 Kh

g  = 9.8 m/s²

F_Y = \ 58.21 N

Then:

\mu \ = \ \frac{64.65 N}{(73.0 kg)(9.8m/s^2) - (58.21 \ N)}

\mu = 0.0984

Thus, the coefficient of friction is = 0.0984

5 0
1 year ago
A basketball rolls off a deck that is 3.2 m from the pavement. The basketball lands 0.75 m from the edge of the deck. How fast w
Aneli [31]
The table is almost perfect. BUT ... since she called ay negative, that means she's calling the upward direction positive-y and the downward direction negative-y. In that case, since the ball moves downward from the deck to the pavement, the change in y should be negative 3.2 m. Everything else in her table is fine. Choice-D is the good one.

Now, regarding the speed of the ball ...
How long does it take to fall 3.2 m ?
Use the formula. D = 1/2 g T^2 .

3.2 = 4.9 T^2.

T^2 = 3.2/4.9

T = √(3.2/4.9) = 0.808 second.

The ball hit the pavement 0.808 second after it rolled off the deck. So that's also the time it took to move the 0.75 m horizontally.

Speed = distance / time

Speed = 0.75 m / 0.808 second

Speed = 0.928 meter/second .
6 0
2 years ago
Read 2 more answers
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