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solong [7]
2 years ago
13

A 1500 kg car is pushing a 4000 kg truck. The car and truck are accelerating at 2.0 m/s^2. Assuming that the frictional force on

the truck is negligible, what force is the truck exerting on the car?
Physics
1 answer:
Crazy boy [7]2 years ago
7 0

To solve this problem we will use the Force equation according to the definition given in Newton's second law. There we have that the Force is equal to

F =ma

Where,

m = mass

a = acceleration

Our values are given as

m_1 = 1500 kg

m_2 = 4000 kg

a = 2.0 m/s^2

Considering that both mass are equal to one, we have that:

F = (m_1+m_2)* a

F = (1500 + 4000)(2.0)

F = 11000 N = 11kN

Therefore the truck exert a force on the car of 11kN

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Two children stand on a platform at the top of a curving slide next to a backyard swimming pool. At the same moment the smaller
victus00 [196]

1.

Answer:

a) It is less

Explanation:

By energy conservation we can say that initial potential energy of both child must be equal to the final kinetic energy of the two child.

Since initially they are at same height so we will say that initial potential energy will be given as

mgH and MgH

so the child with greater mass has more energy and hence smaller child will reach with smaller kinetic energy

2.

Answer:

b. The two speeds are equal.

Explanation:

As we know by mechanical energy conservation law we have

mgh = \frac{1}{2}mv^2

v = \sqrt{2gh}

since both child starts at same height so here they both will reach the bottom at same speed

3.

Answer:

c. The two accelerations are equal

Explanation:

Since we know that average acceleration of the motion is given as

a = \frac{v_f - v_i}{\Delta t}

since here initial and final speeds are same so they both must have same average acceleration here.

5 0
2 years ago
How much energy does a 50 kg rock have if it is sitting on the edge of a 15 m cliff?
noname [10]

Answer:

7350 J

Explanation:

The gravitational potential energy of the rock sitting on the edge of the cliff is given by:

U=mgh

where

m is the mass of the rock

g is the gravitational acceleration

h is the height of the cliff

In this problem, we have

m = 50 kg

g = 9.8 m/s^2

h = 15 m

Substituting numbers into the formula, we find:

U=(50 kg)(9.8 m/s^2)(15 m)=7350 J

3 0
2 years ago
An electric power plant uses energy from burning coal to generate steam at 450∘C. The plant is cooled by 20∘C water from a nearb
Goryan [66]

Answer:

40 MJ (D)

Explanation:

Quantity of heat (Qh) = 100 MJ

temperature of steam (Th) = 450°c = 450 + 273 = 723 K

emperature of water (TI) = 20 °c = 20 + 273 = 293 k

efficiency = (Qh-Qi)/Qh = (Th-Ti)/Th

 \frac{100x10x^{6}-Qi }{100x10^{6}} = \frac{723-293}{723}

100x10^{6} - Qi= 0.5947 x 100 x 10 ^{6}

100x10^{6} - (0.5947 x 100x10^{6}) = Qi

Qi = 40.5 MJ equivalent to 40 MJ (D)

6 0
2 years ago
Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
Stels [109]

This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide.  Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after.  Subtract this from the the system total and you will have the momentum of the other object after the collision.  Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities.  They are vectors, so direction matters.  Typically moving to the right is positive (+) and moving to the left is negative (-).  It is not clear from your question which direction the objects are moving before and after the collision.

6 0
2 years ago
Read 2 more answers
A bird flies at an average velocity of 3.60 m/s for 18.4 s. How far does it travel? (unit=m)
jarptica [38.1K]
First, you have to write what you know:

V = 3.60 m/s
D = ?
T = 18.4 s

Next, you plug everything into this formula:

V = D/T
3.60 m/s = ?/18.4 s

Then, you multiply 3.60 m/s and 18.4 s

D = 66.24 m

5 0
2 years ago
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