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maks197457 [2]
2 years ago
5

Which of the following would increase the strength of an electromagnet ?

Physics
2 answers:
AleksAgata [21]2 years ago
6 0
<span>More coils of wire around the magnetic material. More current through the wire</span>
GalinKa [24]2 years ago
5 0

Increasing the number of coils and Increasing the power of the Voltage supply.

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Your teacher burns a piece of steel wool in class, demonstrating the chemical property, flammability. You are curious to see wha
LekaFEV [45]

Answer:

I assume by "which" of these you're looking for an example. Water freezing into ice or water, or evaporation, the process of turning from liquid into vapor, would not be chemical changes.

Explanation:

These are physical changes because they do not form a new substance, a chemical change requires a change in the chemical makeup of the substance.

3 0
2 years ago
You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s
TEA [102]
I think the correct answer would be A. If you are waiting to turn left into a small parking lot and a car is approaching from the opposite direction has a turn signal on, then you should wait until the other car starts its turn before making your turn. According to the general law on making a left turn, left turns should yield to the oncoming traffic. The vehicle that arrives in the intersection first would have the right of way to turn left. However, when there are two vehicles arrives at the intersection almost at the same time, then the one on the right would have the right of way.
8 0
2 years ago
The length of a 60 W, 240 Ω light bulb filament is 60 cm Remembering that the current in the filament is proportional to the ele
faust18 [17]

Answer:

Finally current will be

i = 0.35 A

Explanation:

As we know that power of the bulb is given by the formula

P = \frac{V^2}{R}

now we have

P = 60 W

R = 240 ohm

so we have

60 = \frac{V^2}{240}

V = 120 Volts

now the current in the bulb is given as

i = \frac{V}{R}

i = \frac{120}{240} = 0.5 A

now when length of the filament is double

so the resistance of the wire also gets double

so we have

P = \frac{V^2}{R}

60 = \frac{V^2}{480}

V = 169.7 volts

now the current in the bulb is given as

V = i R

169.7 = i(480)

i = 0.35 A

8 0
2 years ago
The grooved pulley of mass m is acted on by a constant force F through a cable which is wrapped securely around the exterior of
Sidana [21]

Answer:

Answer; v= 1.2654m/s

T= 110.76N

Explanation:

Apply Momentum Principle

Fdtro - Mgridt = Iow +Mvr

Fdtro - Mgridt = mK2 v/r1 + Mvr1

85 x 3x 0.345 -11 x 9.81 x 0.23 x 3 =30 x 0.25 x 0.25 x v/0.23 + 11 x v x 0.23 =

v = 1.2654m/s

To find the timed average value

Tdt -Mgdt =MV

T x 3 - 11 x 9.81 x 3 = 11 x 0.778

T= 110.76N

3 0
2 years ago
To start the analysis of this circuit you must write energy conservation (loop) equations. Each equation must involve a round-tr
REY [17]

Answer:

Explanation:

Electric field talks about a region around a charged particle or object within which a force would be exerted on other charged particles or objects. to find the electric field inside the bulb we will apply the electric filed formula.

Please kindly check attachment for step by step explaination.

6 0
2 years ago
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