Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²

v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
Answer:
A) 0.0 kJ
Explanation:
Change in the internal energy of the gas is a state function
which means it will not depends on the process but it will depends on the initial and final state
Also we know that internal energy is a function of temperature only
so here the process is given as isothermal process in which temperature will remain constant always
here we know that

now for isothermal process since temperature change is zero
so change in internal energy must be ZERO
Answer:
-209.42J
Explanation:
Here is the complete question.
A balky cow is leaving the barn as you try harder and harder to push her back in. In coordinates with the origin at the barn door, the cow walks from x = 0 to x = 6.9 m as you apply a force with x-component Fx=−[20.0N+(3.0N/m)x]. How much work does the force you apply do on the cow during this displacement?
Solution
The work done by a force W = ∫Fdx since our force is variable.
Since the cow moves from x₁ = 0 m to x₂ = 6.9 m and F = Fx =−[20.0N+(3.0N/m)x] the force applied on the cow.
So, the workdone by the force on the cow is
W = ∫₀⁶°⁹Fx dx = ∫₀⁶°⁹−[20.0N+(3.0N/m)x] dx
= ∫₀⁶°⁹−[20.0Ndx - ∫₀⁶°⁹(3.0N/m)x] dx
= −[20.0x]₀⁶°⁹ - [3.0x²/2]₀⁶°⁹
= -[20 × 6.9 - 20 × 0] - [3.0 × 6.9²/2 - 3.0 × 0²/2]
= -[138 - 0] - [71.415 - 0] J = (-138 - 71.415) J
= -209.415 J ≅ -209.42J
Answer:
The average magnitude of magnetic field B= 0.0433/ d Tesla
(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)
Explanation:
Induced emf
where B= magnetic field
d= breadth of rectangular piece
V= velocity with which the rectangular piece = o.o6m/s
n= no of turns = 10
EMF = 26mV
since d (breadth of the frame) is not given, I will use it as a variable
EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)
From eq 1, we get
B= (EMF)/(n d V)
B= (26 X 0.001) / (10 d 0.06)
B= 0.0433/ d Tesla
Answer:
D40 = 2.56 × D25
so number is 2.56 multiple of stopping distance @ 25 mph
Explanation:
given data
speed = 40 miles / hour
distance = D40
speed limit = 25 miles / hour
distance = D25
to find out
express number a multiple of stopping distance @ 25 mph
solution
we know here stopping distance is directly proportional to (speed)²
so here speed ratio is
initial speed =
so initial speed = 1.6
so
stopping distance increase = (1.6)²
= (1.6)²
= 2.56
so here
D40 = 2.56 × D25
so number is 2.56 multiple of stopping distance @ 25 mph