Answer:
Part a)
Part b)
Explanation:
Part a)
Electric field due to large sheet is given as
now the electric field is given as
Part b)
Now since the electric field is required at same distance on other side
so the field will remain same on other side of the plate
Answer:
t = 103.45 n m
Explanation:
given,
refractive index of cornea = 1.38
refractive index of eye drop = 1.45
wavelength of refractive index = 600 nm
refractive index of eye drop is greater than refractive index of cornea and the air.
Formula used in this case
for constructive interference
At m = 0 for the minimum thickness, so
t = 103.45 n m
the minimum thickness of the film of eyedrops t = 103.45 n m
Answer:
The number of turns is
Explanation:
From the question we are told that
The inner radius is
The outer radius is
The current it carries is
The magnetic field is
The distance from the center is
Generally the number of turns is mathematically represented as
Generally is the permeability of free space with value
So
Answer: 9938.8 km
Explanation:
1 pound-force = 4.48 N
30.0 pounds-force = 134.4 N
The force of gravitation between Earth and object on the surface of is given by:
Where M is the mass of the Earth, m is the mass of the object, R (6371 km) is the radius of the Earth.
At height, h above the surface of the Earth, the weight of the object:
we need to find "h"
taking the ratio of two:
Hence, Pete would weigh 30 pounds at 9938.8 km above the surface of the Earth.
Answer:
Explanation:
Potential due to a charged metallic sphere having charge Q and radius r on its surface will be
v = k Q / r . On the surface and inside the metallic sphere , potential is the same . Outside the sphere , at a distance R from the centre potential is
v = k Q / R
a ) On the surface of the shell , potential due to positive charge is
V₁ =
On the surface of the shell , potential due to negative charge is
V₁ =
Total potential will be zero . they will cancel each other.
b ) On the surface of the sphere potential
=
= 22.5 x 10⁵ V
On the surface of the sphere potential due to outer shell
=
= -9 x 10⁵
Total potential
=( 22.5 - 9 ) x 10⁵
= 13.5 x 10⁵ V
c ) In the space between the two , potential will depend upon the distance of the point from the common centre .
d ) Inside the sphere , potential will be same as that on the surface that is
13.5 x 10⁵ V.
e ) Outside the shell , potential due to both positive and negative charge will cancel each other so it will be zero.