An action-reaction pair would be a pair in which one of the elements exerts a force on the other element (action), and then the other element would respond to this force by exerting another force in the opposite direction (reaction).
From the given choices, we will see that:
For choice A, the moon exerts a force on the earth by pulling it (action) and the earth responds to this force by pulling the moon (reaction in opposite direction of the action).
Therefore, the correct choice would be:
A. <span>The Moon Pulls on Earth, and Earth pulls back on the moon.</span>
<h2>5.3 km</h2>
Explanation:
This question involves continuous displacement in various directions. When it becomes difficult to imagine, vector analysis becomes handy.
Let us denote each of the individual displacements by a vector. Consider the unit vectors
as the unit vectors in the direction of East and North respectively.
By simple calculations, we can derive the unit vectors
in the directions North,
South of West and
North of West respectively.
So Total displacement vector = Sum of individual displacement vectors.
Displacement vector = 
Magnitude of Displacement = 
∴ Total displacement = 
Answer:
House A requires heat at a slightest faster rate than B
Explanation:
House A requires heat at a slightest faster rate than B due to the slight high temperature the furnace A is.
Answer:

Explanation:
The Free Body Diagram of the system formed by the crate and the rope and the reference axis are presented below as an attached image. The equations of equilibrium are introduced hereafter:


After some algebraic handling, the system of equations is reduce to a sole expression:



The minimum force to accelerate the crate from rest is:



Since
, the crate will experiment an acceleration due to the tension exerted. The acceleration of the crate is:

![a = \frac{325\,N}{45\,kg}\cdot [\cos 23^{\textdegree}+(0.410)\cdot \sin 23^{\textdegree}]-(0.410)\cdot (9.807\,\frac{m}{s^{2}} )](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B325%5C%2CN%7D%7B45%5C%2Ckg%7D%5Ccdot%20%5B%5Ccos%2023%5E%7B%5Ctextdegree%7D%2B%280.410%29%5Ccdot%20%5Csin%2023%5E%7B%5Ctextdegree%7D%5D-%280.410%29%5Ccdot%20%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%29)
