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attashe74 [19]
2 years ago
12

Light hits a clear plastic bottle and a granite rock. Which choice most accurately describes the effect of visible light on the

clear plastic and a grey rock?
1. Visible light is absorbed by both the rock and the plastic, making both objects warmer. Visible light is also reemitted by both objects, allowing visible light through the rock and the plastic.

2. Visible light is absorbed by both the rock and the plastic, making both objects warmer. Some of the light hitting the rock is reemitted, allowing visible light through the rock. None of the light hitting the plastic is reemitted.

3. Visible light is absorbed by the rock, making it warmer. Light is also absorbed by the plastic making it warmer. None of the light hitting either object is reemitted.

4.Visible light is absorbed by the rock and the plastic making both objects warmer. Some of the light hitting the plastic is reemitted, allowing visible light through the plastic. None of the light hitting the rock is reemitted.
Physics
2 answers:
balu736 [363]2 years ago
8 0

Answer:

#4 is the accurate answer.

LenKa [72]2 years ago
5 0

Answer:

4

Explanation:

When the light hits an object, it is absorbed, and the energy of it is transferred by the object by heat, thus it warms. When the object is dark the light is not reemitted because the absorption factor of dark color is almost 100%. But, for clear objects, the absorption factor is small, does, some of the light must be reemitted through it.

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yarga [219]
I see the light moving exactly at speed equal to c.

In fact, the second postulate of special relativity states that:
"The speed of light in free space has the same value c<span> in all inertial frames of reference."
</span>
The problem says that I am moving at speed 2/3 c, so my motion is a uniform motion (constant speed). This means I am in an inertial frame of reference, so the speed of light in this frame must be equal to c.
3 0
1 year ago
Block b rests upon a smooth surface. if the coefficients of static and kinetic friction between a and b are μs = 0.4 and μk = 0.
aliina [53]

Given

Weight of the block A, Wa = 20 lb, weight of block B Wb = 50 lb. Applied force to block A, P = 6lb, coefficient of static friction µs = 0.4, coefficient of kinetic friction µk = 0.3. If a force P is applied to the body, no relative motion will take place until the applied force is equal to the force of friction Ff, which is acting opposite to the direction of motion. Magnitude of static force of friction between block A and block B, Fs = µsN, where N is reaction force acting on block A. Now, resolve the forces Fx = max. P = (mA + mB)a,

 

6 = (20 / 32.2 + 50 / 32.2)a

 

2.173a = 6

 

A = 2.76 ft/s^2

 

To check slipping occurs between block A and block B, consider block A:

P – Ff = mAaA

6 – Ff = 1.71

Ff = 4.29 lb

 

And also,

N = wA. We know static friction,

Fs = µsN

Fs = 0.4 x 20

Fs = 8lb

Frictional force is less than static friction. Ff < Fs

<span>Therefors, acceleration of block A, aA = 2.76 ft/s^2, acceleration of block B aB = 2.76 ft/s^2</span>

6 0
1 year ago
One component of a metal sculpture consists of a solid cube with an edge of length 38.9 cm. The alloy used to make the cube has
vovangra [49]

Answer:

The mass of the cube is 420.8 kg.

Explanation:

Given that,

Length of edge = 38.9 cm

Density \rho= 7.15 \times10^{3}\ kg/m^3

We need to calculate the volume of cube

Using formula of volume

V = 38.9^3

V=0.058863\ m^3

We need to calculate the mass of the cube

Using formula of density

\rho = \dfrac{m}{V}

m = V\times\rho

m =0.058863\times7.15 \times10^{3}

m=420.8\ kg

Hence, The mass of the cube is 420.8 kg.

7 0
1 year ago
Dane is standing on the moon holding an 8 kilogram brick 2 metres above the ground. How much energy is in the brick's gravitatio
Nadya [2.5K]

The gravitational potential energy of the brick is 25.6 J

Explanation:

The gravitational potential energy of an object is the energy possessed by the object due to its position in a gravitational field.

Near the surface of a planet, the gravitational potential energy is given by

PE=mgh

where

m is the mass of the object

g is the strength of the gravitational field

h is the height of the object relative to the ground

For the brick in this problem, we have:

m = 8 kg is its mass

g = 1.6 N/kg is the strenght of the gravitational field on the moon

h = 2 m is the height above the ground

Substituting, we find:

PE=(8)(1.6)(2)=25.6 J

Learn more about potential energy:

brainly.com/question/1198647

brainly.com/question/10770261

#LearnwithBrainly

3 0
1 year ago
Read 2 more answers
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Answer:

230

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v = Velocity = 15 m/s

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K=\dfrac{1}{2}mv^2\\\Rightarrow K=\dfrac{1}{2}1500\times 15^2\\\Rightarrow K=168750\ J

Number of accelerations would be given by

n=\dfrac{38880000}{168750}\\\Rightarrow n=230.4

So the number of complete accelerations is 230

8 0
2 years ago
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