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Alika [10]
2 years ago
12

A car is moving on a straight road in a fixed direction at a constant speed of v = 62 km/h with respect to the road. You wish to

state the kinematic vectors of the motion of the car by using a Cartesian coordinate system whose positive x-axis is pointed in the direction of the motion of the car and the origin is fixed at some point on the road. A. What is the expression for the velocity of the car, using the speed v and the unit vectors i,j, and k?
B. What is the x-component of the position vector, in units of kilometers, at time t=0.015 hr?
Physics
1 answer:
Angelina_Jolie [31]2 years ago
5 0

Answer:

A) V=62 i + 0 j + 0 k

B) X=0.93 km

Explanation:

A) In this situation we are talking about a car moving only in the X- axis, hence the velocity of the car is:

V=62 i + 0 j + 0 k

Where the unit vectors i, j and k represent the components x, y and z in the cartesian plane.

In this sense, each unit vector is defined to have a magnitude of exactly one (1).

B) Velocity is defined as the variation of position in time, if this car is moving only along the x direction we will have:

V=\frac{X}{t}

Clearing the position:

X=V.t

X=(62 km/h)(0.015 h)

X=0.93 km

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If no frictional work is considered, then the energy of the system (the driver at all positions is conserved.

Let
position 1 = initial height of the diver (h₁), together with the initial velocity (v₁).
position 2 = final height of the diver (h₂) and the final velocity (v₂).

The initial PE = mgh₁ and the initial KE  = (1/2)mv₁²
where g = acceleration due to gravity,
m = mass of the diver.
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PE in position 1 is converted into KE due to the loss in height from position 1 to position 2.
 
Therefore
(KE + PE) ₁ = (KE + PE)₂

Evaluate the given answers.
A) The total mechanical energy of the system increases.
     FALSE

B) Potential energy can be converted into kinetic energy but not vice versa.
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C) (KE + PE)beginning = (KE + PE) end.
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D) All of the above.
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raketka [301]

Answer:

- 3 meter

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A dog has started motion from +3 meter. ...(Given)

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Maximum negative distance = (-) (3)

Maximum negative distance = -3 meter

Hence, maximum negative distance is -3 meter.

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An 80.0-kg object is falling and experiences a drag force due to air resistance. The magnitude of this drag force depends on its
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Answer:

The terminal speed of this object is 12.6 m/s

Explanation:

It is given that,

Mass of the object, m = 80 kg

The magnitude of drag force is,

F_{drag}=12v+4v^2

The terminal speed of an object is attained when the gravitational force is balanced by the gravitational force.

F_{drag}=mg

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