Answer:
choosing a material that will show warning before it fails
Explanation:
According to my research on different architectural engineering techniques, I can say that based on the information provided within the question this is an example of choosing a material that will show warning before it fails. By choosing aluminum he can detect certain failures a long time before it actually happens since aluminum shows signs of wear and tear and doesn't just break immediately.
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When the metals touch
together, half the charge of the charged metal flows to the other because the
electrons all repel each other. Therefore this also means that each metal ball
contains the same amount of electrons. Each ball has 5^10 electrons, this is
equivalent to a total charge of:
Q1 = Q2 = (1.602 * 10^-19
coulombs / electron) 5^10 electrons = Q
Q = 1.564 * 10^-12 C
Now using the Coulombs
law to find for the electric force:
F = k q1 q2 / r^2 = k (Q)^2
/ r^2
where k is a contant = 9
* 10^9 N m^2 / C^2
r = the distance of the
two metals = 0.2 m
So,
F = (9 * 10^9 N m^2 /
C^2) (1.564 * 10^-12 C)^2 / (0.2 m)^2
F = 5.51 * 10^-13 N
Since the two metals
repel therefore they are the one which exerts the force hence the magnitude
must be negative:
<span>F = - 5.51 * 10^-13 N</span>
A sound wave. Because in a vacuum there is no medium in a vacuum. And the only wave that requires a medium to travel through is a sound wave.
Answer:
B
Explanation:
Work done can be said to be positive if the applied force has a component to be in the direction of the displacement and when the angle between the applied force and displacement is positive.
In 1 and 2 work done is positive