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1 year ago

2. The water is then heated to its boiling point. Calculate the specific latent heat of

Physics

1 answer:

Law Incorporation [45]1 year ago

6 0

Answer:

2465 J/g

Explanation:

The amount of energy required to boil a sample of water already at boiling point is given by

$Q=m\lambda_v$

where

m is the mass of the water sample

$\lambda_v$ is the specific latent heat of vaporization of water

In this problem, we know

$Q=813,600 J$

$m = 330 g$

Solving the equation for $\lambda_v$ , we find

$\lambda_v = \frac{Q}{m}=\frac{813600}{330}=2465 J/g$

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There are some missing data in the text of the problem. I've found them online:
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