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liq [111]
2 years ago
8

A car is driving east at 120. km/h from Toronto to Ottawa. The distance between the two cities is 425.5 km, how long will it tak

e for the driver to reach Ottawa?
Physics
1 answer:
Ket [755]2 years ago
4 0

Answer:

The time it will take for the driver to reach Ottawa is 3 hours 32 minutes and 45 seconds

Explanation:

The given parameters are;

Speed of the car = 120 km/h

Distance from Toronto to Ottawa = 425.5 km

The formula for speed is given as follows;

Speed = Distance/Time

Therefore, to find the time duration it takes from Toronto to Ottawa, we have;

Time duration = Distance from Toronto to Ottawa/(Speed of the car)

The time duration = 425.5/120 = 3.54583 hours = 212.75 min = 12765 seconds

The time it takes from Toronto to Ottawa while driving at 425.5 km/h = 12765 seconds.

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11–8 Consider a heavy car submerged in water in a lake with a flat bottom. The driver’s side door of the car is 1.1 m high and 0
Greeley [361]

Answer:

Explanation:

position of centre of mass of door from surface of water

= 10 + 1.1 / 2

= 10.55 m

Pressure on centre of mass

atmospheric pressure + pressure due to water column

10 ⁵ + hdg

= 10⁵ + 10.55 x 1000 x 9.8

= 2.0339 x 10⁵ Pa

the net force acting on the door (normal to its surface)

= pressure at the centre x area of the door

= .9 x 1.1 x 2.0339 x 10⁵

= 2.01356 x 10⁵ N

pressure centre will be at 10.55 m below the surface.

When the car is filled with air or  it is filled with water , in both the cases pressure centre will lie at the centre of the car .

7 0
2 years ago
How could the combustibility of a substance influence how the substances used
aliina [53]

Answer:

Combustibility is a measure of how easily a substance bursts into flame, through fire or combustion. This is an important property to consider when a substance is used for construction or is being stored. It is also important in processes that produce combustible substances as a by-product.

Explanation:

3 0
2 years ago
A particular metal has a work function of 1.05 eV. A light is shined onto this metal with a corresponding wavelength of 324 nm.
LenaWriter [7]

Answer:

Velocity of electron will be v=0.986\times 10^6m/sec              

Explanation:

We have given work function of metal \Phi =1.05eV=1.05\times 1.6\times 10^{-19}J=1.68\times 10^{-19}J

Wavelength of the light \lambda =324nm=324\times 10^{-9}m

So energy is given by E=\frac{hc}{\lambda }, here h is plank's constant and c is speed of light

So E=\frac{6.6\times 10^{-34}\times3\times 10^8}{324\times 10^{-9} }=6.11\times 10^{-19}j

For a metal we know that E=\Phi +KE_{MAX}

So KE_{MAX}=E-\Phi =6.11\times 10^{-19}-1.68\times 10^{-19}=4.43\times 10^{-19}

Now kinetic energy is given by KE=\frac{1}{2}mv^2

4.43\times 10^{-19}=\frac{1}{2}\times 9.11\times 10^{-31}v^2

v=0.986\times 10^6m/sec

So velocity of electron will be v=0.986\times 10^6m/sec

7 0
2 years ago
In a race, a runner traveled 12 meters in 4.0 seconds as she accelerated uniformly from rest. The magnitude of the acceleration
mestny [16]
<span>The runner is moving by uniformly accelerated motion, starting from rest (so, his initial velocity is zero). The law of motion of the runner is
</span>x(t) =  \frac{1}{2}  at^2<span>
where x(t) is the distance covered after time t, and a is the acceleration of the runner. By re-arranging the formula, we get
</span>a= \frac{2S}{t^2}<span>
We know the runner has covered a distance of S=12m in t=4.0 s, and if we plug these numbers into the equation, we find the acceleration of the runner: 
</span>a= \frac{2S}{t^2} = \frac{(2*12m)}{(4s)^2} =1.5 m/s^2<span>
</span>
5 0
2 years ago
In recent years, astronomers have found planets orbiting nearby stars that are quite different from planets in our solar system.
Leto [7]

Answer:

g= 3.86 m/s^2

Explanation:

given : Kepler-12b, has a diameter that is 1.7 times that of Jupiter (R_Jupiter = 6.99 × 10^7 m), but a mass that is only 0.43 that of Jupiter (M_Jupiter = 1.90 × 10^27 kg ).

to calculate gravity we use the formula

g = GM/r^2

g = 6.67×10^-11 × 0.43×1.9×10^27/( 1.7×6.99×10^7)^2

g = 3.859 ~ 3.86 m/s^2

4 0
2 years ago
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