Answer:
T= 354.65 N
Explanation:
Given that
ρ= 7800 kg/m³
L= 58 cm
d=1.34 mm
f= 311 Hz
T= Tension
Speed of wave ,V
V = f λ
V = f L
V= 311 x 0.58 m/s
V=180.38 m/s
Area of cross sectional
A= πr² mm²
A= 3.14 x 0.67² mm²
A=1.41 mm²
Mass = Density x Volume
m=0.0109 kg/m
Tension ,T
T= 0.0109 x 180.38² N
T= 354.65 N
Answer:
The distance of the speaker B would be 1 meters.
Explanation:
Given that,
Frequency of the waves emitted, f = 172 Hz
You are 8.00 m from the speaker.
The speed of sound in air to be 344 m/s.
The wavelength of the wave is given in terms of frequency and the speed of sound. It is given by :
Since, the distance from the Speaker A is 8 m which is the integral multiple of the wavelength. Let the closest distance of the speaker B would be given by :
So, the distance of the speaker B would be 1 meters. Hence, this is the required solution.
Answer:
The workdone is
Explanation:
The free body diagram is shown on the first uploaded image
From the question we are given that
The force is on the force gauge
The distance that Magnus pulled the bus
Generally the workdone by the tension force on Magnus is
This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )
Substituting value we have
