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hodyreva [135]
2 years ago
6

The energy gaps between the valence and conduction bands are called band gaps. For silicon, the band gap is 1.1 eV; for fused si

lica glass, it is 9.3 eV.
What is the wavelength λ of a photon that has energy 1.1eV?
The cut off between visible and infrared light is usually said to be somewhere between 700 and 800nm. Why is silicon transparent to most infrared light but opaque to visible light?
a) Visible photons have greater energy than the gap, so they can be absorbed whereas infrared photons pass through.
b) Visible photons have greater energy than the gap, so they can’t interact with the silicon as the infrared photons can.
c) Infrared photons have less energy than the gap, and so, unlike visible photons, they can be absorbed and reemitted from the material.
d) Infrared photons have less energy than the gap, and so they are only partially absorbed whereas visible photons are fully absorbed.
Physics
1 answer:
kotegsom [21]2 years ago
6 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
<span>d) Infrared photons have less energy than the gap, and so they are only partially absorbed whereas visible photons are fully absorbed.</span>
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The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and for water is 4186 J/kg⋅C∘.
abruzzese [7]

Answer:

The equilibrium temperature is

21.97°c

Explanation:

This problem bothers on the heat capacity of materials

Given data

specific heat capacities

copper is Cc =390 J/kg⋅C∘,

aluminun Ca = 900 J/kg⋅C∘,

water Cw = 4186 J/kg⋅C∘.

Mass of substances

Copper Mc = 235g

Aluminum Ma = 135g

Water Mw = 825g

Temperatures

Copper θc = 255°c

Water and aluminum calorimeter θ1= 16°c

Equilibrium temperature θf =?

Applying the principle of conservation of heat energy, heat loss by copper equal heat gained by aluminum calorimeter and water

McCc(θc-θf) =(MaCa+MwCw)(θf-θ1)

Substituting our data into the expression we have

235*390(255-θf)=

(135*900+825*4186)(θf-16)

91650(255-θf)=(3574950)(θf-16)

23.37*10^6-91650*θf=3.57*10^6θf- +57.2*10^6

Collecting like terms and rearranging

23.37*10^6+57.2*10^6=3.57*10^6θf+91650θf

8.2*10^6=3.66*10^6θf

θf=80.5*10^6/3.6*10^6

θf =21.97°c

5 0
2 years ago
Um navio cargueiro proveniente do Oceano Atlântico passa a navegar nas águas menos densas do rio Amazonas. Em comparação com a s
LUCKY_DIMON [66]

Answer:

Mas eu acho q é o empuxo será igual e a porção imersa do navio será maior.

Explanation: SE

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8 0
2 years ago
A 248-g piece of copper is dropped into 390 mL of water at 22.6 °C. The final temperature of the water was measured as 39.9 °C.
Sedaia [141]

Answer:

335°C

Explanation:

Heat gained or lost is:

q = m C ΔT

where m is the mass, C is the specific heat capacity, and ΔT is the change in temperature.

Heat gained by the water = heat lost by the copper

mw Cw ΔTw = mc Cc ΔTc

The water and copper reach the same final temperature, so:

mw Cw (T - Tw) = mc Cc (Tc - T)

Given:

mw = 390 g

Cw = 4.186 J/g/°C

Tw = 22.6°C

mc = 248 g

Cc = 0.386 J/g/°C

T = 39.9°C

Find: Tc

(390) (4.186) (39.9 - 22.6) = (248) (0.386) (Tc - 39.9)

Tc = 335

7 0
2 years ago
Recall that in the equilibrium position, the upward force of the spring balances the force of gravity on the weight. Use this co
natima [27]

Recall that in the equilibrium position, the upward force of the spring balances the force of gravity on the weight is given below.

Explanation:

Measure unstretched length of spring, L.  E.g. L = 0.60m.

Set mass to a convenient value (e.g. m = 0.5kg).

Hang mass.

Measure new spring length, L'. E.g. L' = 0.70m.

Calculate extension: e = L' - L = 0.70 – 0.60 = 0.10m

Use mg = ke (in equilibrium weight = tension)

k = mg/e

Don't know what value you are using for example.  Suppose it is 10N/kg (same thing as 10m/s²).

k = 0.5*10/0.10 = 50 N/m

Repeat for a few different masses.  (L always stays the same.)

Take the average of your k values.

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2 years ago
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noname [10]
I will say it is B; the Inverse square law. 
Ohms has to do with electricity and the other 2 just have to do with regular physics.
7 0
2 years ago
Read 2 more answers
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