A tennis ball bounces on the floor three times, and each time it loses 23.0% of its energy due to heating. how high does it boun
1 answer:
You might be interested in
Answer:
The simplified expression is
Explanation:
From the question we are told that
So simplifying we have
Thus the simplified formula is
Answer:
= 85.89 ° C
Explanation:
The linear thermal expansion process is given by
ΔL = L α ΔT
For the three-dimensional case, the expression takes the form
ΔV = V β ΔT
Let's apply this equation to our case
ΔV / V = -0.507% = -0.507 10-2
ΔT = (ΔV / V) 1 /β
ΔT = -0.507 10⁻² 1 / 1.15 10⁻³
ΔT = -4.409
–T₀ = 4,409
= T₀ - 4,409
= 90.3-4409
= 85.89 ° C
Answer:
A) 12P
Explanation:
The power produced by a force is given by the equation
where
W is the work done by the force
T is the time in which the work is done
At the beginning in this problem, we have:
W = work done by the force
T = time taken
So the power produced is
Later, the force does six times more work, so the work done now is
And this work is done in half the time, so the new time is
Substituting into the equation of the power, we find the new power produced:
So, 12 times more power.
Because charges are positioned on a square the force acting on one charge is the same as the force acting on all others.
We will use superposition principle. This means that force acting on the charge is the sum of individual forces. I have attached the sketch that you should take a look at.
We will break down forces on their x and y components:
Let's figure out each component:
Total force acting on the charge would be:
We need to calculate forces along x and y axis first( I will assume you meant micro coulombs, because otherwise we get forces that are huge).
Now we can find the total force acting on a single charge:
As said before, intensity of the force acting on charges is the same for all of them.
We will use superposition principle. This means that force acting on the charge is the sum of individual forces. I have attached the sketch that you should take a look at.
We will break down forces on their x and y components:
Let's figure out each component:
Total force acting on the charge would be:
We need to calculate forces along x and y axis first( I will assume you meant micro coulombs, because otherwise we get forces that are huge).
Now we can find the total force acting on a single charge:
As said before, intensity of the force acting on charges is the same for all of them.