What is the total kinetic energy of a 0.15 kg hockey puck sliding at 0.5 m/s and rotating about its center at 8.4 rad/s? The dia
1 answer:
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Answer:
28.8 %
Explanation:
The efficiency of an engine is given by:
where
W is the useful work done
is the heat in input
For this machine, we have
W = 15.0 kJ is the work done
is the heat exchausted to the cold reservoir, so the total amount of heat in input is
And so the efficiency is
which corresponds to 28.8 %.
I think they just want you to rewrite it two other ways:
First thing plot a right angle with angle of elevation of 35degrees as shown in figure then use SOHCAHTOA.
Ay/Helicopter = sin 35
Ay = 86 sin 35 = 36.8237
Ax/Helicopter = cos 35
Ax = 86 cos 35 = 77.7175
Note: I ignore the negative signs coz they signify direction
Answer:
Q1: 3.2km
Q2: 4.8K
Explanation:
Q1:
So db is the distance of bird, and dr is the distance of runner
db = 2vr and the distance of bird is going to be 2 times greater than the runner.
formulas: db = 2vr & db = 2dr
- db = 2dr
- L + (L - x) = 2x
- 2L - x = 2x
- 2L = 3x
- x =
L
Insert it in x = L
(2.4km) = 1.6km
Now we use formula db = 2dr
- db = 2L - x
- db = 2(2.4km) - 1.6km
- <u>db = 3.2km</u>
Q2:
Formulas: Vr = L /Δt & Vb = db/Δt
- Vr = L/ Δt ⇒ Δt =
(Km cancel each other)
- Vb = db/Δt ⇒ db = VbΔt
- 13.6km/hr
- <u>4.8km</u>
(hr cancel each other)
Hope it helps you :)