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Alinara [238K]
2 years ago
5

To understand how the two standard ways to write the general solution to a harmonic oscillator are related.

Physics
1 answer:
photoshop1234 [79]2 years ago
6 0

Answer:

a)   C = A cos φ , S = A sin φ,  b)   φ = tan⁻¹ (S / C) ,  A² = C² + S²

Explanation:

a) The two forms given are equivalent, let's start by developing the double angle

            Cos (a + b) = cos a cos b - sin a sin b

Call us

           a  = wt     and      b = φ

           x = A (cos wt cosφ- sin wt sin φ

the second equation is

           x = C cos wt + S  sin wt

Let's match

           C cos wt + S sin wt = A cos φ coswt - a sin φ sin wt

The coefficients of the cosine and breasts must be equal,

         C = A cos φ

          S = A sin φ

b) Divide the last two expressions

          tan φ = S / C

          φ = tan⁻¹ (S / C)

Let's square the two equations

         C² = A² cos² φ

         S² = A² sin² φ

Let's add

        C² + S² = A² (cos² φ + sin² φ)

The part in brackets vouchers1

        A² = C² + S²

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iren2701 [21]

Answer:

Option D

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Explanation:

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The air outside the convertible is moving faster than the air inside the convertible. This leads to a higher pressure zone just below the surface of the roof (inside the car) causing the roof of the convertible to bulge upwards

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Which of the following is NOT a good way to reduce fuel consumption?
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Answer:

Explanation:

d

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An green hoop with mass mh = 2.8 kg and radius rh = 0.13 m hangs from a string that goes over a blue solid disk pulley with mass
Otrada [13]
The only force on the system is the mass of the hoop F net = 2.8kg*9.81m/s^2 = 27.468 N The mass equal of the rolling sphere is found by: the sphere rotates around the contact point with the table. 
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7 0
2 years ago
Submarine a travels horizontally at 11.0 m/s through ocean water. it emits a sonar signal of frequency f 5 5.27 3 103 hz in the
xeze [42]
Velocity of submarine A is vs = 11.0m/s
frequency emitted by submarine A. F = 55.273 × 10∧3HZ
Velocity of submarine B = vO = 3.00m/s
The given equation is
f' = ((V + vO) ((v - vS)) × f
The observer on submarine detects the frequency f'.
The sign of vO should be positive as the observer of submarine B is moving away from the source of submarine A.
The speed of the sound used in seawater is 1533m/s
The frequency which is detected by submarine B is 
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6 0
2 years ago
A standing wave of the third overtone is induced in a stopped pipe, 2.5 m long. The speed of sound is The frequency of the sound
NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

To find the frequency of the sound produced by the pipe you use the following formula:

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You replace the values of n, L and vs in order to calculate the frequency:

f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz

hence, the frequency of the third overtone is 102 Hz

8 0
2 years ago
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