<span>Poet Kuangchi Chang did not remain in China long enough to be "re-educated." Following the Communist takeover he fled to the United States. His poem "Garden of My Childhood" describes China before the revolution as a peaceful, idyllic garden with a violent horde rapidly approaching. A vine, the wind, and the sea are each personified, and each beckons for him to run. It is not until "eons later," when he is "worlds away," that his "running is all done," and he finds himself at his destination: another garden, just like the one he had left behind.</span>
Answer:
T₂ =602 °C
Explanation:
Given that
T₁ = 227°C =227+273 K
T₁ =500 k
Gauge pressure at condition 1 given = 100 KPa
The absolute pressure at condition 1 will be
P₁ = 100 + 100 KPa
P₁ =200 KPa
Gauge pressure at condition 2 given = 250 KPa
The absolute pressure at condition 2 will be
P₂ = 250 + 100 KPa
P₂ =350 KPa
The temperature at condition 2 = T₂
We know that
T₂ = 875 K
T₂ =875- 273 °C
T₂ =602 °C
This can be calculated with the law of conservation of energy. The sky lift is starting with the speed v= 15.5 m/s and all of it's kinetic energy Ek is transformed to potential energy Ep so the energies have to be equal: Ep=Ek.
Since Ek=(1/2)*m*v² where m is mass and v is the speed, Ep=m*g*h, where m is mass, g= 9.81 m/s² and h is height. Now:
Ek=Ep
(1/2)*m*v²=m*g*h, masses cancel out,
(1/2)*v²=g*h, divide by g to get the height,
(1/2*g)*v²=h and now plug in the numbers:
h=12.245 m. Height of the hill rounded to the nearest tenth is h=12.25 m
Answer:
Ft
Explanation:
We are given that
Initial velocity=u=0
We have to find the magnitude of p of the momentum of the particle at time t.
Let mass of particle=m
Applied force=F
Acceleration, 
Final velocity , 
Substitute the values
We know that
Momentum, p=mv
Using the formula
Answer:
the internal energy of the gas is 433089.52 J
Explanation:
let n be the number of moles, R be the gas constant and T be the temperature in Kelvins.
the internal energy of an ideal gas is given by:
Ein = 3/2×n×R×T
= 3/2×(5.3)×(8.31451)×(24 + 273)
= 433089.52 J
Therefore, the internal energy of this gas is 433089.52 J.
