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Alex17521 [72]
2 years ago
12

Isabella deja caer accidentalmente un bolígrafo desde su balcón mientras celebra que resolvió satisfactoriamente un problema de

física Al suponer que la resistencia del aire es baja cuántos segundos tarda el bolígrafo en alcanzar una rapidez de 19.62 m/s
Physics
1 answer:
jok3333 [9.3K]2 years ago
8 0

Answer:

i cant read spanish lol

Explanation:

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When an ice pack is applied to an injury, thermal energy from the injured area transfers to the ice, causing the blood vessels w
Shkiper50 [21]
It is conduction I believe
8 0
2 years ago
Read 2 more answers
A penny is placed on a rotating turntable. Where on the turntable does the penny require the largest centripetal force to remain
Artyom0805 [142]

Answer:

m = mass of the penny

r = distance of the penny from the center of the turntable or axis of rotation

w = angular speed of rotation of turntable

F = centripetal force experienced by the penny

centripetal force "F" experienced by the penny of "m" at distance "r" from axis of rotation is given as

F = m r w²

in the above equation , mass of penny "m"  and angular speed "w" of the turntable is same at all places. hence the centripetal force directly depends on the radius .

hence greater the distance from center , greater will be the centripetal force to remain in place.  

So at the edge of the turntable , the penny experiences largest centripetal force to remain in place.

Explanation:

5 0
2 years ago
At a given point on a horizontal streamline in flowing air, the static pressure is â2.0 psi (i.e., a vacuum) and the velocity is
Nastasia [14]
At a point on the streamline, Bernoulli's equation is
p/ρ + v²/(2g) = constant
where
p = pressure
v = velocity
ρ = density of air, 0.075 lb/ft³ (standard conditions)
g = 32 ft/s²

Point 1:
p₁ = 2.0 lb/in² = 2*144 = 288 lb/ft²
v₁ = 150 ft/s

Point 2 (stagnation):
At the stagnation point, the velocity is zero.

The density remains constant.
Let p₂ = pressure at the stagnation point.
Then,
p₂ = ρ(p₁/ρ + v₁²/(2g))
p₂ = (288 lb/ft²) + [(0.075 lb/ft³)*(150 ft/s)²]/[2*(32 ft/s²)
     = 314.37 lb/ft²
     = 314.37/144 = 2.18 lb/in²

Answer: 2.2 psi

5 0
2 years ago
Trained dolphins are capable of a vertical leap of 7.0 m straight up from the surface of the water - an impressive feat. Suppose
dmitriy555 [2]

Answer:14 m

Explanation:

Given

Vertical jump make by the dolphin is given by h=7\ m

Suppose the dolphin jump with an initial velocity of u

so u is given by u^2=2\cdot g\cdot h

If dolphin launches at an angle \theta then maximum horizontal range is given by

assuming the of Dolphin to be Projectile so range is given by

R=\frac{u^2\sin 2\theta }{g}

substitute the value of u^2

R=\frac{2\times 9.8\times 7\sin 2\theta }{9.8}

R=2h\sin 2\theta

Range will be maximum for \theta =45^{\circ}

thus R_{max}=2\times 7\times 1=14\ m

                                     

3 0
2 years ago
To crossing over the flooded canal.
zubka84 [21]

Answer:

F. jumping

Explanation:

you can't throw/toss yourself, you cant roll over water, catching?, you cant run over water, jumps are bigger than hops

4 0
2 years ago
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