What team are you talking about
Answer:
W = 9533.09 Watt
Explanation:
given,
diameter of pipe inlet, d₁ = 10 cm
r₁ = 5 cm
diameter of pipe outlet, d₂ = 15 cm
r₂= 7.5 cm
head upto water level is to rise = 60 + 5
= 65 m
flow rate = 0.015 m³/s
we know
A₁ v₁ = A₂ v₂ = Q
π r₁² v₁ = π r₂² v₂ = 0.015
v₂ = 0.848 m/s
v₁ = 1.908 m/s
Applying Bernoulli's equation
P_p is the pump pressure
Power of the pump
W = P_p x Q
W = 635539.32 x 0.015
W = 9533.09 Watt
T = √(h)/(0.5)(9.81)
t = √(25)/(4.905)
t = √5.1
t = 2.26 seconds
hope this helps and have a great day :)
Answer:
4/10 of L.
Explanation:
A stopped pipe is a pipe with one closed end and one opened end. it is also called a closed pipe.
The fundamental mode of a stopped pipe is also called its fundamental frequency, and is f₁=v/4L.
Where f₁=fundamental frequency, v= velocity of sound, L= Length of pipe.
The fifth harmonic of the stopped pipe f₅ =5v/4L .................(1)
For an open pipe,
Fundamental mode is also called fundamental frequency f₁₀=v/2l₀ .......... (2)
Where f₁₀ = fundamental frequency of a closed pipe, v= velocity of sound and l₀=length of the resulting open pipe.
from the question, the fundamental mode of the resulting open pipe = The fifth harmonic of the original stopped pipe.
∴ f₅=f₁₀
⇒5v/4L = v/2l₀
Equating v from both side of the equation,
⇒ 5/4L = 1/2l₀
Cross multiplying the equation,
5×2l₀ = 4L× 1
10l₀ = 4L
Dividing both side of the equation by the coefficient of l₀ i.e 10
10l₀/10 = 4L/10
∴ l₀ = 4/10(L)
∴ 4/10 of L must be cut off
