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Alja [10]
2 years ago
12

What is the risk when a pwc passes too closely behind another boat?

Physics
1 answer:
Lemur [1.5K]2 years ago
4 0
The risk when a PWC (Personal Water Craft) passes too closely behind another boat is creating a blind spot. Blind spot can create a collision. 
The boat will block the view of the PWC of oncoming boats, as well as the oncoming boat's view of the PWC.So, that's why it is very important to maintain a proper lookout while turning the PWC and beware of your blind spots.
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A more realistic car would cause the wheels to spin in a manner that would result in the ground pushing it forward with a consta
-Dominant- [34]

The car would go from  zero to 58.0 mph in 2.6 sec.

Since the force on the car is constant, therefore the acceleration of the car would also be constant.

Now for constant acceleration we can use the equation of motion

Using first equation of motion to calculate the acceleration of the car

v=u+at

29=0+a×1.30       ...... Eq. (1)

Again using the first equation of motion

58=0+a*t             ....... Eq. (2)

Dividing eq. (2) with equation 1

t=2×1.3

t=2.6 sec

7 0
2 years ago
If there is a potential difference v between the metal and the detector, what is the minimum energy emin that an electron must h
beks73 [17]
The electrical potential energy of a charge q located at a point at potential V is given by
U=qV
Therefore, if the charge must move between two points at potential V1 and V2, the difference in potential energy of the charge will be
\Delta U = q (V_2 -V_1)=q \Delta V

In our problem, the electron (charge e) must travel across a potential difference V. So the energy it will lose traveling from the metal to the detector will be equal to 
\Delta U = e V
Therefore, if we want the electron to reach the detector, the minimum energy the electron must have is exactly equal to the energy it loses moving from the metal to the detector:
E_{min} = \Delta U = eV
5 0
2 years ago
A point charge q1 = 4.50 nC is located on the x-axis at x = 1.95 m , and a second point charge q2 = -6.80 nC is on the y-axis at
Vinvika [58]

Answer:

Explanation:

One charge is situated at x = 1.95 m . Second charge is situated at y = 1.00 m

These two charges are situated outside sphere as it has radius of .365 m with center at origin. So charge inside sphere = zero.

Applying Gauss's theorem

Flux through spherical surface = charge inside sphere / ε₀

= 0 / ε₀

= 0 Ans .

3 0
2 years ago
In Paul Hewitt's book, he poses this question: "If the forces that act on a bullet and the recoiling gun from which it is fired
Sauron [17]
They have different accelerations because of their masses. According to Newton's Second Law, an objects acceleration is inversely proportional to its mass. Therefore the object with the larger mass, in this case the gun, will have a smaller acceleration. In the same way, the less massive object, being the bullet, will have a higher acceleration.

Hope this helps :)
4 0
2 years ago
Can light cause the rubber to become solid? Why or why not? Does it matter what type of light she shines on the rubber?
ELEN [110]

Answer:

Yes, ultraviolet light can turn a rubber into solid due to prolong exposure.

Explanation:

A rubber is a material with an elastic property, causing it to be deform by an external force but takes its shape when the force is removed. Light is an electromagnetic wave which causes the sensation of vision. It transfers energy to a medium during propagation through the medium.

Generally, most light do not cause hardness of a rubber. But an ultraviolet light can cause rubber to become solid over a period of time. This is possible if there is a prolong exposure of the rubber, and because of the evaporation of volatiles in the polymer material. Ultraviolet light are known to cause a rubber to become solid.

8 0
2 years ago
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