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Dmitrij [34]
2 years ago
11

Junior slides across home plate during a baseball game. If he has a mass of 115 kg, and the coefficient of kinetic friction betw

een him and the ground is 0.35, what is the force of friction acting on him?
Physics
2 answers:
uysha [10]2 years ago
6 0

Answer:

like the other person said, it is 395

Explanation:

tatyana61 [14]2 years ago
4 0

Weight Force of Junior = m g = 115kg x 9.81 m/s^2 = 1128.15N then compute for the friction force


Friction Force= WF x (coefficient of kinetic friction) = 1128.15N x 0.35 =  394.8525N or 395N

 

But you can compute in a straightway:

Solution:

= 115 x 9.81 x 0.35

= 394.85

= 395 N

 

It will still give the same results.

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Two resistors of resistances R1 and R2, with R2>R1, are connected to a voltage source with voltage V0. When the resistors are
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Answer

The Value of  r  = 0.127

Explanation:

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 And from Ohm law

                           I_s =\frac{ V}{R_T}

                            I_s  = \frac{V_0}{R_1 +R_2} ---(1)

The mathematical representation of the two resistors connected in parallel  is

                    R_T = \frac{1}{R_1} +\frac{1}{R_2}

                          = \frac{R_1 R_2}{R_1 +R_2}

From the question I_p =10I_s

          =>                 I_p =10I_s = \frac{V_0 }{\frac{R_1R_2}{R_1 +R_2} }  = \frac{V_0 (R_1 +R_2)}{R_1 R_2}---(2)

     Dividing equation 2 with equation 1

       =>                 \frac{10I_s}{I_s} =\frac{\frac{V_0 (R_1 +R_2)}{R_1 R_2}}{\frac{V_0}{R_1 +R_2}}

                                  10 = \frac{(R_1+R_2)^2}{R_1 R_2}----(3)

We are told that    r = \frac{R_1}{R_2} \ \ \ \ \  = > R_1 = rR_2

From equation 3  

                            10 = \frac{(1-r)^2}{r}

=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  1+r^2 + 2r = 10r

=> \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ r^2 -8r+1 = 0

Using the quadratic formula

                             r =\frac{-b\pm \sqrt{(b^2 - 4ac)} }{2a}

        a = 1  b = -8 c =1  

                              =  \frac{8 \pm\sqrt{((-8)^2- (4*1*1))} }{2*1}

                               r= \frac{8+ \sqrt{60} }{2}  \ or \  r = \frac{8 - \sqrt{60} }{2}

                              r = \ 7.87\ or \  r \  = \ 0.127

Now  r =  0.127 because it is the least value among the obtained values

                               

                                   

                             

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