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ruslelena [56]
2 years ago
11

a student wants to push a box of books with the mass of 50 kg in 3 m horizontally towards the location of the shelves where the

books will be placed. how much work to bw done to push the box of books in 3 m if the force exerted is 120 N?
Physics
1 answer:
irina1246 [14]2 years ago
8 0

Answer:

The work done is 360 J.

Explanation:

Given that,

Mass = 50 kg

Distance =3 m

We need to calculate the work done

The work done is equal to the product of force and displacement.

Using formula of work done

W = F\cdot d

W = Fd\cos\theta

Where, F = force

D = distance

θ = Angle between force and displacement

Put the value into the formula

W=120\times3\cos0^{\circ}

W=360\ J

Hence, The work done is 360 J.

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Answer:

1331.84 m/s

Explanation:

t = Time taken

u = Initial velocity

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s = Displacement = 490 km

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g = Acceleration due to gravity = 1.81 m/s² = a

From equation of linear motion

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -1.81\times 490000}\\\Rightarrow u=1331.84\ m/s

The speed of the material must be 1331.84 m/s in order to reach the height of 490 km

3 0
2 years ago
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A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w
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Answer:

25.82 m/s

Explanation:

We are given;

Force exerted by baseball player; F = 100 N

Distance covered by ball; d = 0.5 m

Mass of ball; m = 0.15 kg

Now, to get the velocity at which the ball leaves his hand, we will equate the work done to the kinetic energy.

We should note that work done is a measure of the energy exerted by the baseball player.

Thus;

F × d = ½mv²

100 × 0.5 = ½ × 0.15 × v²

v² = (2 × 100 × 0.5)/0.15

v² = 666.67

v = √666.67

v = 25.82 m/s

4 0
1 year ago
Based on the time measurements in the table, what can be said about the speed of the car on the lower track as compared to the h
raketka [301]

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1.a

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Explanation:

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A spring with a spring constant of 0.70 N/m is stretched 1.5 m. What was the force?
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Answer:

1.05 N

Explanation:

K = 0.7 N/m

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from Hooke's law of elasticity

F = Ke

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A dog of mass 10 kg sits on a skateboard of mass 2 kg that is initially traveling south at 2 m/s. The dog jumps off with a veloc
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Answer:

17 m/s south

Explanation:

m_1 = Mass of dog = 10 kg

m_2 = Mass of skateboard = 2 kg

v = Combined velocity = 2 m/s

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u_2 = Velocity of skateboard

In this system the linear momentum is conserved

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The velocity of the skateboard will be 17 m/s south as the north is taken as positive

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