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Helga [31]
2 years ago
9

A dolphin is able to tell in the dark that the ultrasound echoes received from two sharks come from two different objects only i

f the sharks are separated by 3.60 meters, one being that much farther away than the other. (a) If the ultrasound has a frequency of 105 kHz, show this ability is not limited by its wavelength m < 3.50 m (b) If this ability is due to the dolphin's ability to detect the arrival times of echoes, what is the minimum time difference (in ms) the dolphin can perceive? ms
Physics
1 answer:
Vlad1618 [11]2 years ago
6 0

Answer:

a) Wavelength of the ultrasound wave = 0.0143 m <<< 3.5m, hence its ability is not limited by the ultrasound's wavelength.

b) Minimum time difference between the oscillations = Period of oscillation = 0.00952 ms

Explanation:

The frequency of the ultrasound wave = 105 KHz = 105000 Hz. The speed of ultrasound waves in water ≈ 1500 m/s. Wavelength = ?

v = fλ

λ = v/f = 1500/105000 = 0.0143 m <<< 3.5m

This value, 0.0143m is way less than the 3.5m presented in the question, hence, this ability is not limited by the ultrasound's wavelength.

b) Minimum time difference between the oscillations = The period of oscillation = 1/f = 1/105000 = 0.00000952s = 0.00952 ms

Hope this helps!

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Answer:

Check Explanation

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In the theory of relativity,

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u = (u' + v)/[1 + (u'v/c²)]

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u = 1.3c/[1 + (0.4c²/c²)]

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8 0
2 years ago
At the instant that the velocity of the crate is v⃗ =(3.40m/s)ι^+(2.20m/s)j^, what is the instantaneous power supplied by this f
Zigmanuir [339]
I found some missing information about this problem online. We are given the force:
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Power is defined as the rate of doing work. 
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If we assume that force is not changing (it's constant) with time we get:
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Finally, we get:
P=F_i\cdot v_i+F_j\cdot v_j=(-7.50N)(3.40\frac{m}{s})+(3.00N)(2.20\frac{m}{s})=&#10;-18.9 W


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A hoop is rolling (without slipping) on a horizontal surface so it has two types of kinetic energy: translational kinetic energy
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Answer:

\dfrac{T}{K}=1

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T=\dfrac{1}{2}I\omega^2

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T=\dfrac{1}{2}\times MR^2\times (\dfrac{v}{R})^2..............(2)

From equation (1) and (2) :

\dfrac{T}{K}=1

Therefore, the ratio of the translational kinetic energy to the rotational kinetic energy is 1.

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A mercury thermometer has a glass bulb of interior volume 0.100 cm3 at 10°c. the glass capillary 10) tube above the bulb has an
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2 years ago
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