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ASHA 777 [7]
2 years ago
13

Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent

ial speeds? Juan and Kuri move the same distance in one revolution, but Juan completes the revolution in less time and has a higher speed. Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed. Juan moves a shorter distance in less time than Kuri, but their speeds are the same. Juan and Kuri complete one revolution in the same time, so they have the same speed.
Physics
2 answers:
Licemer1 [7]2 years ago
6 0

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

d = 2\pi r

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

v = \frac{2\pi r}{T}

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

LuckyWell [14K]2 years ago
4 0

Answer:

B on edge

Explanation:

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Explanation:

One can use the right hand rule to illustrate the direction of travel of an electromagnetic and thereby get the directions of the electric field, magnetic field and direction of travel of the wave.

The right hand rule states that the direction of the thumb indicate the direction of travel of the electromagnetic wave (<em>in this case the -z direction</em>) and the curling of the fingers point in the direction of the magnetic field  B→ (<em>in this case the +x direction</em>), therefore, the electric field direction E→ is in the direction of the fingers which would be pointed towards the +y direction.

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1 year ago
The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a
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Answer:

147.45 Hz

\Delta f=f_{Lr}-f_{Se}

Explanation:

v = Speed of sound in water = 1482 m/s

v_w = Speed of whale = 4.95 m/s

The difference in frequency is given by

\Delta f=f\dfrac{v+v_w}{v-v_w}-f\dfrac{v}{v-v_w}\\\Rightarrow \Delta f=f_{Lr}-f_{Se}

Frequency of the wave in stationary condition

f_{Lr}=f\dfrac{v+v_w}{v-v_w}

Ship's frequency which is reflected back

f_{Se}=f\dfrac{v}{v-v_w}

f_{Se}=22\ kHz

\mathbf{\Delta f=f_{Lr}-f_{Se}}

\Delta f=f_{Lr}-f_{Se}\\\Rightarrow \Delta f=22\times \dfrac{1482+4.95}{1482-4.95}-22\\\Rightarrow \Delta f=0.14745\ kHz\\\Rightarrow \Delta f=147.45\ Hz

The difference in wavelength is 147.45 Hz

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To solve this problem it is necessary to use the given proportions of power and energy, as well as the energy conversion factor in Jules to Calories.

The power is defined as the amount of energy lost per second and whose unit is Watt. Therefore the energy loss rate given in seconds was

P = \frac{E}{t} \rightarrow E= Energy, t = time

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P = 62\frac{J}{s} (\frac{86400s}{1day})

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E = 5356800J \frac{1KCal}{4.184*10^{6}J}

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The number of kilocalories (food calories) must be 1279.694 KCal

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