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Rzqust [24]
2 years ago
5

De Vico Comet orbits the Sun every 74.0 years and has an orbital eccentricity of 0.96. Find the comet's average distance from th

e Sun (semimajor axis). Express your answer in astronomical units to three significant figures.
Physics
1 answer:
Debora [2.8K]2 years ago
5 0

Answer: The comet's average distance from the sun is 17.6AU

Explanation:

From Kepler's 3rd Law, P^2=a^3

Where P is period in years

and a is length of semi-major axis or the average distance of the comet to the sun.

Given the orbital period to be 74 years

74^2 =a^3

5476 = a^3

Cube root of 5476 =a

17.626 = a

Approximately a= 17.6 AU

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In some amazing situations, people have survived falling large distances when the surface they land on is soft enough. During a
OleMash [197]

Answer:

-3413 ft/s2

Explanation:

We need to know the velocity with which he landed on the snow.

He 'dropped' from 512 feet. This is the displacement. His initial velocity is 0 and the acceleration of gravity is 32 ft/s2.

We use the equation of mition

v^2 = u^2 + 2as

v and u are the initial and final velocities, a is the acceleration and s is the displacement. Putting the appropriate values

v^2 = 0^2 + 2\times32\times512

v = \sqrt{2\times32\times512} = 128\sqrt{2}

This is the final velocity of the fall and becomes the initial velocity as he goes into the snow.

In this second motion, his final velocity is 0 because he stops after a displacement of 4.8 ft. We use the same equation of motion but with different values. This time, u=128\sqrt{2}, v = 0 and s = 4.8 ft.

0^2 = (128\sqrt{2})^2 + 2a\times4.8

a = -\dfrac{2\times128^2}{2\times4.8} = -3413

Note that this is negative because it was a deceleration, that is, his velocity was decreasing.

5 0
2 years ago
A horse and rider are racing to the right with a speed of 21\,\dfrac{\text m}{\text s}21 s m ​ 21, start fraction, start text, m
Marrrta [24]

Answer:

a=-4.2 m/s²

Explanation:

The horse  riding so inital velocity is given finally the rider stops so the final velocity is zero.

initial velocity =Vi= 21 m/s

final velocity =Vf= 0 m/s

distance covered = S=52 m

By using 2nd equation of motion we can find the acceleration

 2aS=Vf² -Vi²

   a=(-441)/104

   a=-4.2 m/s²

So the accceleration is 4.2 m/s².

7 0
2 years ago
Read 2 more answers
A slide whistle is an open-closed tube with an adjustable plunger that changes the length. You are playing the slide whistle and
Serjik [45]

Answer:

df / ft = -n 12          n= 1, 3, 5, ...

Explanation:

The speed of sound is

         v = λ f

         

In a whistle that we approach by an open tube at one end and closed at the other, standing waves occur, which has a node in the closed part and a maximum in the open pate, whereby wavelength and the distance of the tube are related, the fundamental wave is

         λ₁ = 4L

   The harmonics are

        λ₃ = 4L / 3

        λ₅ = 4L / 5

The general formula

       λₙ = 4L / n              

with n = 1, 3, 5,…

We substitute and clear in the first equation

           f = v n / 4L                        n = 1, 3, 5,…

Let's use derivatives to find the frequency change

           df / dt = v n /4  dL⁻¹ / dt

          d / dt (1/L) = - 1 / L² dL / dt

Where dL / dt = 8 cm / s

We replace

         df / dt = - n v / L2 dL / dt

Let's calculate

         df / dt = - n 340/152 8

         df / ft = -n 12          n= 1, 3, 5, ...

4 0
2 years ago
If you pull a resistant puppy with its leash in a horizontal direction, it takes 80 N to get it going. You can then keep it movi
netineya [11]

Answer:

The coefficient of static friction between the puppy and the floor is 0.7273.

Explanation:

The horizontal force applied to move the puppy from a steady state has to be greater than the force of static friction, after it is moving the force needs to be equal to be greater than the force of dynamic friction in order to maintain its movement. The force of static friction is given by:

F_s = \mu_s*N

Where F_s is the static friction force, \mu_s is the coefficient of static friction and N is the normal force. Since there's no angle on the flor the normal force is equal to the weight of the puppy, therefore, N = 110\text{ N}, to make the puppy moving we need to use a force of 80 N, therefore, F_s = 80 \text{ N}, so we can solve for the coefficient as shown below:

80 = \mu_s*110\\\mu_s = \frac{80}{110} = 0.7273\\

The coefficient of static friction between the puppy and the floor is 0.7273.

5 0
2 years ago
If a force of 26 N is exerted on two balls, one with a mass of 0.52 kg and the other with a mass of 0.78 kg, the ball with the m
gogolik [260]
False is the correct answer
6 0
2 years ago
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