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1 year ago

At what location in the refrigerator is the most thermal energy removed?

Physics

1 answer:

Bas_tet [7]1 year ago

3 0

Answer:

Condenser

Explanation:

The refrigerator work on a simple cycle:

1- When the cold air inside the refrigerator starts to get warm, it loses its thermal energy ot the cold refrigerant which is flowing inside an evaporator. This thermal energy converts the refrigerant into a gas.

2- The refrigerant, in a form of gas, goes to the compressor. The compressor compresses it and increases its temperature even more.

3- Then it goes to the condenser where it loses its most of the thermal energy to the condenser coils. When it loses the energy. it comes back to liquid form.

4.The refrigerant flow back to the evaporator

Cycle continuous

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A cat accelerates from rest to 10m/s when it sees a dog. This takes 2 seconds. What was the acceleration of the cat

Nookie1986 [14]

The formula is a= chance in velocity/time
A=10-0/2
A=10/2
A=5 m/s^2 (meters per second squared)

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1 year ago

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iren2701 [21]

I think the best answer is option one. The first thing to focus on when creating a workout plan is <span>determining the frequency of the activity. It is important took look at how much time do you have to do things in order to manage your tasks daily and you can give enough time for each activity.</span>

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"I know how many electrons the atom has, and I know how many protons it has, but I don't know whether or not it is neutral," a f

finlep [7]

The atom is neutral (no electric charge)

Explanation:

An atom consists of:

- A nucleus, containing protons (positively charged) and neutrons (no electric charge)

- Electrons (negatively charged), orbiting around the nucleus

The charge of one proton is equal in magnitude (but opposite in sign) to that of an electron, and it is

$e=1.6\cdot 10^{-19} C$

Moreover, for a normal atom, the number of protons in the nucleus is equal to the number of electrons around it.

This means that for a normal atom, the net charge of it is zero, since the total charge of the protons balance that of the electrons.

So, the answer to the question is that the atom is neutral.

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brainly.com/question/2757829

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1 year ago

Follow these steps to solve this problem: Two identical loudspeakers, speaker 1 and speaker 2, are 2.0 m apart and are emitting

horsena [70]

Answer:

Explanation:

Wave length of sound from each of the speakers = 340 / 1700 = .2 m = 20 cm

Distance between first speaker and the given point = 4 m.

Distance between second speaker and the given sound

= √ 4² + 2² = √16 +4 = √20 = 4.472 m

Path difference = 4.472 - 4 = .4722 m.

Path difference / wave length = 0.4772 / 0.2 = 2.386

This is a fractional integer which is neither an odd nor an even multiple of half wavelength. Hence this point of neither a perfect constructive nor a perfect destructive interference.

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2 years ago

A child of mass m is at the edge of a merry-go-round of diameter d. When the merry-go-round is rotating with angular acceleratio

dem82 [27]

Answer:

The torque on the child is now the same, τ.

Explanation:

It can be showed that the external torque applied by a net force on a rigid body, is equal to the product of the moment of inertia of the body with respect to the axis of rotation, times the angular acceleration.
In this case, as the movement of the child doesn't create an external torque, the torque must remain the same.
The moment of inertia is the sum of the moment of inertia of the merry-go-round (the same that for a solid disk) plus the product of the mass of the child times the square of the distance to the center.
When the child is standing at the edge of the merry-go-round, the moment of inertia is as follows:

$I_{to} = I_{d} + m*r^{2} = m*\frac{r^{2}}{2} + m*r^{2} = \frac{3}{2}* m*r^{2} (1)$

So, τ = 3/2*m*r²*α (2)

When the child moves to a position half way between the center and the edge of the merry-go-round, the moment of inertia of the child decreases, as the distance to the center is less than before, as follows:

$I_{t} = I_{d} + m*\frac{r^{2}}{4} = m*\frac{r^{2}}{2} + m*\frac{r^{2}}{4} = \frac{3}{4}* m*r^{2} (3)$

Since the angular acceleration increases from α to 2*α, we can write the torque expression as follows:

τ = 3/4*m*r² * (2α) = 3/2*m*r²

same result than in (2), so the torque remains the same.

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1 year ago