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LenKa [72]
1 year ago
7

Leanne is riding a bike. The forward force from her pedalling is 18N. There is a backward force of 6N from friction and a backwa

rd force of 12N from air resistance. Does the speed of the bike increase, decrease or not change?
Physics
2 answers:
Gelneren [198K]1 year ago
7 0
The speed of the bike does not change because the total force that is pushing her back is 18 Newtons and her forwards force is 18 newtons is her force is balanced and therefore will not change
olchik [2.2K]1 year ago
4 0
the net force acting on the bike is=
18 - 6 - 12 = 0 N.

Since the net force acting on the bike is zero, the bike is moving with constant velocity. Therefore, the speed of the bike does not change.
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A biker travels at an average speed of 18 km/hr along a 0.30 km straight segment of a bike path. How much time (in hours) does t
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Answer: 0.016 h

Explanation:

\text{Average speed} = \frac{\text {Total Distance}}{\text {total time taken}}

It is given that, biker has an average speed = 18 km/h

Total distance traveled = 0.30 km

Therefore, time taken by biker to travel this distance:

\Rightarrow \text{total time taken} = \frac{0.30 km}{18 km/h}=0.016 h

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A 20.0 kg rock is sliding on a rough , horizontal surface at8.00 m/s and eventually stops due to friction .The coefficient ofkin
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Haley noticed a small spot on her skin that turned out to be skin cancer. Which treatment is her doctor most likely to use?
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A gas of helium atoms at 273 k is in a cubical container with 25.0 cm on a side. (a) what is the minimum uncertainty in momentum
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6 0
2 years ago
A chair of mass 30.0 kg is at rest on a horizontal floor. The floor is not frictionless. You push on the chair with a force of 8
miv72 [106K]
First make sure you draw a force diagram. You should have Fn going up, Fg going down, Ff going left and another Fn going diagonally down to the right. The angle of the diagonal Fn (we'll call it Fn2) is 35° and Fn2 itself is 80N. Fn2 can be divided into two forces: Fn2x which is horizontal, and Fn2y which is vertical. Right now we only care about Fn2y.

To solve for Fn2y we use what we're given and some trig. Drawing out the actual force of Fn2 along with Fn2x and Fn2y we can see it makes a right triangle, with 80 as the hypotenuse. We want to solve for Fn2y which is the opposite side, so Sin(35)=y/80. Fn2y= 80sin35 = 45.89N

Next we solve for Fg. To do this we use Fg= 9.8 * m. Mass = 30kg, so Fg = 9.8 * 30 = 294N.

Since the chair isn't moving up or down, we can set our equation equal to zero. The net force equation in the vertical direction will be Fn + Fn2y -Fg = 0. If we plug in what we know, we get Fn + 45.89 -294 = 0. Then solve this algebraically.

Fn +45.89 -294 = 0
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You'll get a more accurate answer if you don't round Fn2y when solving for it, it would be something along the lines of 45.88611 etc
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1 year ago
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