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LenKa [72]
2 years ago
7

Leanne is riding a bike. The forward force from her pedalling is 18N. There is a backward force of 6N from friction and a backwa

rd force of 12N from air resistance. Does the speed of the bike increase, decrease or not change?
Physics
2 answers:
Gelneren [198K]2 years ago
7 0
The speed of the bike does not change because the total force that is pushing her back is 18 Newtons and her forwards force is 18 newtons is her force is balanced and therefore will not change
olchik [2.2K]2 years ago
4 0
the net force acting on the bike is=
18 - 6 - 12 = 0 N.

Since the net force acting on the bike is zero, the bike is moving with constant velocity. Therefore, the speed of the bike does not change.
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Pressure and volume changes at a constant temperature can be calculated using
Crank
It can be calculated using Boyle's Law.  A.
3 0
2 years ago
A bullet is fired through a board, 14.0 cm thick, with its line of motion perpendicular to the face of the board. if it enters w
bazaltina [42]
Okay, here is my stab at this, I hope it helps!

You know the bullet's initial velocity, V₀ = 450 m/s
You know the final velocity, V = 220 m/s
You also know how long the bullet accelerates (actually decelerates), 14cm, or .14 m

With this information, you learn that you need this equation.

V² = V₀² + 2a (x - x₀), because we have all the information except a, which is the acceleration. So putting it into the equation, it looks like this.

(220m/s)² = (450m/s)² +2a(.14m - 0m)

I'll let you solve the rest, but here are some hints.  Your answer will be really big because the bullet slows down really quickly in a really small distance, and you answer will be negative, because this acceleration is causing the bullet to go slower, which is also called deceleration. Hope that helps!
4 0
2 years ago
Read 2 more answers
What mass needs to be attached to a spring with a force constant of 7N/m in order to make a simple harmonic oscillator oscillate
Alex_Xolod [135]

Answer:

Mass will be 4.437 kg

Explanation:

We have given force constant k = 7 N/m

Time period of oscillation T = 5 sec

So angular frequency \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{5}=1.256rad/sec

We know that angular frequency is given by

\omega =\sqrt{\frac{k}{m}}

1.256 =\sqrt{\frac{7}{m}}

Squaring both side

1.577 =\frac{7}{m}

m = 4.437 kg

6 0
2 years ago
Now suppose the initial velocity of the train is 4 m/s and the hill is 4 meters tall. If the train has a mass of 30000 kg, what
hoa [83]

Answer:

<h2>187,500N/m</h2>

Explanation:

From the question, the kinectic energy of the train will be equal to the energy stored in the spring.

Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².

Equating both we will have;

1/2 mv² = 1/2ke²

mv² = ke²

m is the mass of the train

v is the velocity of then train

k is the spring constant

e is the extension caused by the spring.

Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m

Substituting this values into the formula will give;

30000*4² =  k*1.6²

k = \frac{30,000*16}{1.6^2}\\ \\k = \frac{480,000}{2.56}\\ \\k = 187,500Nm^{-1}

The value of the spring constant is 187,500N/m

7 0
2 years ago
When the mass of the cylinder increased by a factor of 3, from 1.0 kg to 3.0 kg, what happened to the cylinder’s gravitational p
Gnesinka [82]

Answer:

It increased by a factor of 3.

Explanation:

The gravitational potential energy of an object is given by

U=mgh

where

m is the mass

g is the gravitational acceleration

h is the heigth of the object relative to some reference point (for instance, the ground)

As we see from the formula, the gravitational potential energy is directly proportional to the mass, m: therefore, if the mass of the cylinder is increased by a factor 3, then the gravitational potential energy will also increase by a factor 3.

6 0
2 years ago
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