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valentina_108 [34]
2 years ago
11

Compare and contrast a tanker truck carrying a liquid load and a truck carrying solid objects

Physics
1 answer:
givi [52]2 years ago
4 0

Answer:

Explanation:

  • When carrying a liquid load the tanker will have pressure on a larger area of the container as compared to a tanker truck carrying a solid load.
  • Since the liquid has a property to flow therefore the molecules of the liquid load throughout the bulk will fluctuate more on any movement or vibration than the solid load.
  • The liquid load will require a leak proof container whereas the solid load container has no such restrictions.
  • The solid load will exert the pressure majorly on the bottom surface of the tanker truck whereas the pressure is distributed over the area of contact in case of the liquid load.
  • Solid load can be bound by the fixtures whereas the liquid load requires compartments in the tanker to minimize the fluctuations on acceleration and deceleration.
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In the circular motion of the hammer, the centripetal force is given by
F=m \frac{v^2}{r}
where m is the mass of the hammer, v its tangential speed and r is the distance from the center of the motion, i.e. the length of the hammer.
Using the data of the problem, we find:
F=m \frac{v^2}{r}=(7.26 kg) \frac{(31.95 m/s)^2}{1.215 m}=6100 N
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An electron moving at right angles to a 0.1 T magnetic field experiences an acceleration of 6 × 1015 m.s-2. What is the speed of
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Explanation:

It is given that,

Magnetic field, B = 0.1 T

Acceleration, a=6\times 10^{15}\ m/s^2

Charge on electron, q=1.6\times 10^{-19}\ C    

Mass of electron, m=9.1\times 10^{-31}\ kg    

(a) The force acting on the electron when it is accelerated is, F = ma

The force acting on the electron when it is in magnetic field, F=qvB\ sin\theta

Here, \theta=90

So, ma=qvB

Where

v is the velocity of the electron

B is the magnetic field

v=\dfrac{ma}{qB}

v=\dfrac{9.1\times 10^{-31}\ kg\times 6\times 10^{15}\ m/s^2}{1.6\times 10^{-19}\ C\times 0.1\ T}

v = 341250  m/s

or

v=3.41\times 10^5\ m/s

So, the speed of the electron is 3.41\times 10^5\ m/s

(b) In 1 ns, the speed of the electron remains the same as the force is perpendicular to the cross product of velocity and the magnetic field.

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A toy car is given an initial velocity of 5.0 m/s and experiences a constant acceleration of 2.0 m/s656-03-02-00-00_files/i02900
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It would be 17 m/s

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And
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Answer:

1 lb. is 453.592 grams

Explanation:

1lb is 453.592 grams

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By Newton's second law, assuming <em>F</em> is horizontal,

• the net <u>horizontal</u> force on the <u>larger</u> block is

<em>F</em> - <em>µmg</em> = 3<em>mA</em>

where <em>µmg</em> is the magnitude of friction felt by the larger block due to rubbing with the smaller one, <em>µ</em> is the coefficient of static friction between the two blocks, and <em>A</em> is the block's acceleration;

• the net <u>vertical</u> force on the <u>larger</u> block is

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where 4<em>mg</em> is the mag. of the normal force of the surface pushing up on the combined mass of the two blocks, 3<em>mg</em> is the weight of the larger block, and <em>mg</em> is the weight of the smaller block;

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<em>µmg</em> = <em>ma</em>

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<em>mg</em> - <em>mg</em> = 0

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(You should be able to draw your own FBD's based on the forces mentioned above.)

(c) Solve the equations above for <em>A</em> and <em>a</em> :

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<em>a</em> = <em>µg</em>

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