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viva [34]
2 years ago
5

The following pairs of surfaces are pushed together with the same amount of force. Between which pair of surfaces will friction

be the greatest?
A. two pieces of sandpaper
B. two pieces of waxed paper
C. a painted surface and a piece of sandpaper
D. a painted surface and a piece of waxed paper


Juan and his friends want to build their own go-karts and race down their street. According to Newton’s Second Law of Motion, which of these will help Juan to win the race?
A. increasing the mass of his go-kart
B. increasing the amount of inertia the go-kart has
C. decreasing the net force applied to the go-kart
D. decreasing the mass of his go-kart
Physics
2 answers:
Aleks [24]2 years ago
5 0
A.  The friction between two pieces of sandpaper is greater than
the friction between any of the pairs of surfaces.

D.  Juan should decrease the mass of his go-kart.  Then any force
that pushes it forward will give it greater forward acceleration.
ozzi2 years ago
5 0

c. a painted surface and a piece of sandpaper

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A square block of steel with volume 10 cm3 and mass of 75 g is cut precisely in half. The density of the two smaller pieces is n
dem82 [27]
A. Density only depends on the substance. It doesn't matter whether you have a little chip of it or a supertanker full of it ... the density doesn't change.
4 0
2 years ago
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Th e heat capacity of air is much smaller than that of water, and relatively modest amounts of heat are needed to change its tem
Darina [25.2K]

Answer:

Q=1005 J

t= 0.67 sec

Explanation:

Lets take condition of room is 1 atm and 25°C.

Heat capacity ,c = 21 J /K.mol

If we assume that air is ideal gas that

P V = n R T

V= 5.5\times 6.5\times 3\ m^3

V=107.25\ m^3

V=107.25\times 1000 L

V= 107250 L

At STP number of moles given as

n=\dfrac{V}{V_{at\ S.T.P.}}

V=22.4 L at S.T.P.

n=\dfrac{107250}{22.4}\ moles

n=4787.94 moles

n= 4.784 Kmoles

So heat required to raise 10°C temperature

Q = n x c x ΔT

Q = 4.78794 x 21 x 10

Q=1004.64 J

Time t

t= Q/P

P= 1.5 KW

t = 1.004.64 /1.5

t= 0.66 sec

4 0
2 years ago
Read 2 more answers
Imagine two people standing at placemark A and placemark E, looking at each other across the fault. Which of the following state
lord [1]

Answer:

To both observers, the land opposite them is moving to the right.

Explanation:

I have this class too. and there is also a quizlet with all the answers to the rest of the other questions. Trust me its right .

https://quizlet.com/261219090/oce-1001-chapter-2-flash-cards/

5 0
2 years ago
Water, of density 1000 kg/m3, is flowing in a drainage channel of rectangular cross-section. The width of the channel is 15 m, t
Rom4ik [11]

Answer:

Water flowing rate=  (300000kg/s) = (300000l/s)

Explanation:

First with the section of the channel, the depth of the water and the speed of the fluid we can determine the volume of fluid that circulates per second through the channel:

Volume per time= 15m × 8m × (2.5m/s)= 300 m³/s

With this volume of circulating fluid per second elapsed, we multiply it by the density of the water to determine the kilograms or liters of water that circulate through the channel per second elapsed:

Water flowing rate= (300m³/s) × (1000kg/m³)= (300000kg/s) = (300000l/s)

Taking into account that 1kg of water is approximately equal to 1 liter of water.

8 0
2 years ago
According to the work-energy theorem, if work is done on an object, its potential and/or kinetic energy changes. Consider a car
Leni [432]

Answer:

The force of the car engine.

Explanation:

The work- energy theorem states that the work done on an object is equal to the change in its kinetic energy. Its expression is given by :

W=\dfrac{1}{2}m(v^2-u^2)

Also, W = F.d

Fd=\dfrac{1}{2}m(v^2-u^2)

Where

F is the force applied by the engine of car

d is the displacement

m is the mass of an object

u is the initial speed

v is the final speed

So, the force of the car engine increased the car’s kinetic energy. Hence, this is the required solution.

6 0
2 years ago
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