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2 years ago

Waves inwhich the particles vibrate at right angles to direction is called

1 answer:

5 0

When the particles of a medium are vibrating at right angles to the direction of energy transport, then the wave is a ____ wave. In transverse waves, particles of the medium vibrate to and from in a direction perpendicular to the direction of energy transport.

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A 4.99 m long rod of negligible weight is attached on one end to a ball joint which allows the rod to rotate in all directions.

Aleksandr [31]

Answer:

The answer is 91.18 Nm

Explanation:

Solution

Recall that

The length of the rod = 4.99 m

∅ = 26°

Force = 62.5N

Now,

T = r * F

The direction of the torque will be in horizontally northward

The torque magnitude is T =r F sin θ

where ∅ will be the angle between r + F θ= 163°

Therefore,

T = 4.99 * 62.5 * sin 163

T =91.18 Nm

6 0

2 years ago

A 45-mH inductor is connected to an ac source of emf with a frequency of 250 Hz and a maximum emf of 20 V. If the voltage across

ruslelena [56]

Answer:

-20v

Explanation:

Data provided in the question as per the given situation

L = 45 mH

f = 250 Hz

V_o = 20V

Based on the above information, let us assume voltage across inductor be V at t

So,

$V = 20 sin (2 \pi \times 250\times t + \frac{\pi}{2})$

t = 2 ms

Now

The voltage at time t = 2.0 ms is

$V_1 = 20 sin (500\times 2\times 10^{-1} \times \pi + \frac{\pi}{2})$

$= 20 sin(\pi + \frac{\pi}{2} )$

= -20 volt

= -20v

We simply solved the above equation so that the correct voltage could come

5 0

2 years ago

Which objects have both potential and kinetic energy? Check all that apply.

wariber [46]

A falling raindrop
Kinetic energy and potential energy are both applied when a body or object is falling.

3 0

2 years ago

Read 2 more answers

Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end

iragen [17]

Answer:

The workdone is $W_d =-4400J$

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

The force is on the force gauge $F = 2750 N$

The distance that Magnus pulled the bus $d = 1.60m$

Generally the workdone by the tension force on Magnus is

$Workdone = Force * displacement \ in \ the \ direction \ of \ force$

$W_d = F * (-d)$

This negative sign show that is tension force is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

$Workdone = - 2750 * 1.60$

$=-4400 J$

7 0

2 years ago

A pickup truck starts from rest and maintains a constant acceleration a0. After a time t0, the truck is moving with speed 25 m/s

Anastaziya [24]

Answer:

the correct answer is c v₁> 12.5 m / s

Explanation:

This is a one-dimensional kinematics exercise, let's start by finding the link to get up to speed.

v² = v₀² + 2 a₁ x

as part of rest v₀ = 0

a₁ = v² / 2x

a₁ = 25² / (2 120)

a₁ = 2.6 m / s²

now we can find the velocity for the distance x₂ = 60 m

v₁² = 0 + 2 a1 x₂

v₁ = Ra (2 2,6 60)

v₁ = 17.7 m / s

these the speed at 60 m

we see that the correct answer is c v₁> 12.5 m / s

5 0

2 years ago