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2 years ago

What is a limitation of the electron cloud model theory that a law about electrons would not have?

Physics

2 answers:

Drupady [299]2 years ago

8 0

Electrons couldn't orbit the nucleus like miniature planets~!

ch4aika [34]2 years ago

4 0

Explanation:

Electron cloud model describes the region in an atom which negatively charged and which has probability to find an electron. according to this model, an electron can move closer or away from the nucleus that is it can be inside the nucleus but according to Bohr's model, an electron is always at a fixed distance from the nucleus. Thus, it is the limitation of the electron cloud model but still it is a widely accepted model.

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There is a 120 V circuit in a house that is a dedicated line for the dishwasher, meaning the dishwasher is the only resistor on

aliya0001 [1]

The info given in the question:

Voltage= 120V

Current=18A

Now we have to find the resistance. To find it use the following formula:

V=IR

Now making R to be the subject of the formula

R=V/I

R=120/18

The answer is 6.67 ohms

As dishwasher is the only resistor in the line the voltage drop is going to be 120V. The resistance values determines the hindrance that is present in the circuit that opposes the free flowing electrons

7 0

2 years ago

Read 2 more answers

Before leaving the house in the morning, you plop some stew in your slow cooker and turn it on Low. The slow cooker has a 160 Oh

guajiro [1.7K]

Answer:

Total charge flow through the cooker is 21600 C

Explanation:

As we know that the current flow through the cooker is given by Ohm's law

here it is given as

$V = i R$

$i = \frac{V}{R}$

$i = \frac{120}{160}$

$i = \frac{3}{4} A$

now the charge flow through it is given as

$Q = i t$

total time is t = 8 hours

$Q = \frac{3}{4}(8 \times 60 \times 60)$

$Q = 21600 C$

7 0

2 years ago

What is the mass of a large dog that weighs 441 newtons

PtichkaEL [24]

Weight, w = mg. g ≈ 9.8 m/s². m = mass in kg. w is weight in N

441 N = m* 9.8

9.8m = 441

m = 441/9.8

m = 45 kg.

Mass of the dog is = 45 kg

5 0

2 years ago

A stationary 1.67-kg object is struck by a stick. The object experiences a horizontal force given by F = at - bt2, where t is th

Usimov [2.4K]

Answer:

$v_{f}$ = 3289.8 m / s

Explanation:

This exercise can be solved using the definition of momentum

I = ∫ F dt

Let's replace and calculate

I = ∫ (at - bt²) dt

We integrate

I = a t² / 2 - b t³ / 3

We evaluate between the lower limits I=0 for t = 0 s and higher I=I for t = 2.74 ms

I = a (2,74² / 2- 0) - b (2,74³ / 3 -0)

I = a 3,754 - b 6,857

We substitute the values of a and b

I = 1500 3,754 - 20 6,857

I = 5,631 - 137.14

I = 5493.9 N s

Now let's use the relationship between momentum and momentum

I = Δp = m $v_{f}$ - m v₀o

I = m $v_{f}$ - 0

$v_{f}$ = I / m

$v_{f}$ = 5493.9 /1.67

$v_{f}$ = 3289.8 m / s

5 0

2 years ago

Suppose you are talking by interplanetary telephone to your friend, who lives on the Moon. He tells you that he has just won a n

Savatey [412]

Answer:

The friend on moon will be richer.

Explanation:

We must calculate the mass of gold won by each person, to tell who is richer. For that purpose we will use the following formula:

W = mg

m = W/g

where,

m = mass of gold

W = weight of gold

g = acceleration due to gravity on that planet

FOR FRIEND ON MOON:

W = 1 N

g = 1.625 m/s²

Therefore,

m = (1 N)/(1.625 m/s²)

m(moon) = 0.6 kg

FOR ME ON EARTH:

W = 1 N

g = 9.8 m/s²

Therefore,

m = (1 N)/(9.8 m/s²)

m(earth) = 0.1 kg

Since, the mass of gold on moon is greater than the mass of moon on earth.

Therefore, the friend on moon will be richer.

7 0

2 years ago