Answer:
2.286 ohm
Explanation:
R1 = 16 ohm
R2 = 8 ohm
R3 = 4 ohm
They all are connected in parallel combination
Let the equivalent resistance is R.
1/R = 1/R1 + 1/R2 + 1/R3
1/R = 1/16 + 1/8 + 1/4
1/R = (1 + 2 + 4) / 16
1/R = 7 / 16
R = 16/7 = 2.286 ohm
Answer:
88.3
Explanation:
Emf in a rotating coil is given by rate of change of flux:
E= dФ/dt=(NABcos∅)/ dt
N: number of turns in the coil= 80
A: area of the coil= 0.25×0.40= 0.1
B: magnetic field strength= 1.1
Ф: angle of rotation= 90- 37= 53
dt= 0.06s
E= (80 × 0.4× 0.25×1.10 × cos53)/0.06= 88.3V
Answer:
d. 37 °C
Explanation:
= mass of lump of metal = 250 g
= specific heat of lump of metal = 0.25 cal/g°C
= Initial temperature of lump of metal = 70 °C
= mass of water = 75 g
= specific heat of water = 1 cal/g°C
= Initial temperature of water = 20 °C
= mass of calorimeter = 500 g
= specific heat of calorimeter = 0.10 cal/g°C
= Initial temperature of calorimeter = 20 °C
= Final equilibrium temperature
Using conservation of heat
Heat lost by lump of metal = heat gained by water + heat gained by calorimeter
Answer:
The total charge on the rod is 47.8 nC.
Explanation:
Given that,
Charge = 5.0 nC
Length of glass rod= 10 cm
Force = 840 μN
Distance = 4.0 cm
The electric field intensity due to a uniformly charged rod of length L at a distance x on its perpendicular bisector
We need to calculate the electric field
Using formula of electric field intensity
Where, Q = charge on the rod
The force is on the charged bead of charge q placed in the electric field of field strength E
Using formula of force
Put the value into the formula
We need to calculate the total charge on the rod
Put the value into the formula
Hence, The total charge on the rod is 47.8 nC.
It is not only the horizontal part of the loop that dips
into the magnetic field. We can neglect or disregard the horizontal parts of
the loop that hollows into the magnetic fields since only the parts
perpendicular to the magnetic field complement to it.
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