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Vlada [557]
2 years ago
10

A forklift does 450 J of work to lift a 150 N hot tub. How high is the hot tub lifted? Round your answer to the nearest whole nu

mber.
The hot tub is lifted BLANK m.
Physics
2 answers:
OLEGan [10]2 years ago
7 0

Answer:

The hot tub is lifted  3 m.

vivado [14]2 years ago
5 0
There are already 2 givens, hence we can do direct substitution to get the answer. To make the process simpler, derive the distance formula from the Work formula.

Work = Force x Distance

Distance = \frac{Work}{Force}


Work is 450J while the force is 150N hot tub

To get the proper units, get the equivalent of Joule to eliminate newton. A joule Is equal to 1 N-m

Distance = \frac{450N-m}{150N}
Distance = 3m

Hence, the hot tub is lifted 3 meters.
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By standard convention, both the electric potential and the the electric potential energy between two charges is taken to be zer
shusha [124]

Answer: at when distance r = infinity.

Explanation: The formulae for the electric potential of an electric charge to an arbitrary point is given by the formulae below

V = q/4πεr

V = electric potential (volts)

q = magnitude of electric charge

ε = permittivity of free space

r = distance between arbitrary point and charge.

In the equation above, it can be seen that only electric potential (v) and distance (r) is a variable, and there is an inverse relationship between them (an increase in one leads to a decrease in the other)

Thus to have zero value of electric potential (v= 0) we have to have the largest value of r ( r = infinity).

Same goes for electric potential energy between two charges, the formulae is given below as

W = q1 *q2/4πεr

W= electric potential energy

q1 = magnitude of first charge.

q2 = magnitude of second charge

ε = permittivity of free space

r = distance between arbitrary point and charge.

Also, all values are constant aside from electric potential energy (w) and distance (r) which have an inverse relationship.

Thus to have zero value of electric potential energy (w =0), we have to get an infinite value of distance ( r =infinity)

6 0
2 years ago
Suppose that a sound source is emitting waves uniformly in all directions. If you move to a point twice as far away from the sou
Helen [10]

Answer:

<em>d. unchanged.</em>

Explanation:

The frequency of a wave is dependent on the speed of the wave and the wavelength of the wave. The frequency is characteristic for a wave, and does not change with distance. This is unlike the amplitude which determines the intensity, which decreases with distance.

In a wave, the velocity of propagation of a wave is the product of its wavelength and its frequency. The speed of sound does not change with distance, except when entering from one medium to another, and we can see from

v = fλ

that the frequency is tied to the wave, and does not change throughout the waveform.

where v is the speed of the sound wave

f is the frequency

λ is the wavelength of the sound wave.

4 0
1 year ago
An underground tunnel has two openings, with one opening a few meters higher than the other. If air moves past the higher openin
klasskru [66]

Answer:

There would be a pressure drop in the direction of the higher opening. This will force air to move in from the lower opening and force it to leave through the higher opening. This will create a convectional movement of air, cooling and ventilating the tunnel.

Explanation:

This is in accordance with bernoulli's law of fluid flow which states that the pressure exerted by a moving fluid is lesser than it would exert if it were at rest.

6 0
2 years ago
If points a and b are connected by a wire with negligible resistance, find the magnitude of the current in the 12.0 v battery.
Marizza181 [45]
V = I * R
Where V is the voltage, I is the current and R is the resistance. Using Ohm's law, you require resistance to find the current through the wire. Technically, if the wire has a resistance of 0, you will get infinite current. But this isn't possible. Maybe the negligible resistance refers to the battery's internal resistance - not the wire's resistance. 
7 0
1 year ago
Suppose I have an infinite plane of charge surrounded by air. What is the maximum charge density that can be placed on the surfa
gregori [183]

Answer:

53.1\mu C/m^2

Explanation:

We are given that

Electric field,E=3\times 10^6V/m

We have to find the value of maximum charge density that can be placed on the surface of the plane before dielectric breakdown of the surrounding air occurs.

We know that

E=\frac{\sigma}{2\epsilon_0}

Where \epsilon_0=8.85\times 10^{-12}

Using the formula

3\times 10^6=\frac{\sigma}{2\times 8.85\times 10^{-12}}

\sigma=3\times 10^6\times 2\times 8.85\times 10^{-12}

\sigma=5.31\times 10^{-5}C/m^2

\sigma=53.1\times 10^{-6}C/m^2=53.1\mu C/m^2

1\mu C=10^{-6} C

3 0
2 years ago
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