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just olya [345]
2 years ago
15

The seeds were sown (change the voice)​

Physics
1 answer:
MaRussiya [10]2 years ago
7 0

Answer:

He sowed the seeds

Explanation:

While the question should have given the person who did the sowing for example the seeds were sown by him/ her/ the farmer/ or any name. Therefore, voice is given in passive and to change passive voice to active voice then the sentence will read as follows assuming that the seeds were sown by him

He sowed the seeds

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Point m is located a distance 2d from the midpoint between the two wires. find the magnitude of the magnetic field b1m created a
Tema [17]

Note: The diagram referred to in the question is attached here as a file.

Answer:

The magnitude of the magnetic field is B = \frac{0.071 \mu I}{d}

Explanation:

The magnetic field can be determined by the relationship:

B = \frac{\mu I}{2\pi R}...............(1)

Were I is the current flowing through the wires

The distance R from point 1 to m is calculated using the pythagora's theorem

R = \sqrt{d^{2} + (2d)^{2}  }

R = \sqrt{5d^{2} } \\R = d\sqrt{5}

Substituting R into equation (1)

B = \frac{\mu I}{2\pi d\sqrt{5} }

B = \frac{0.071 \mu I}{d}

3 0
2 years ago
A person who weighs 625 N is riding a 98-N mountain bike. Suppose that the entire weight of the rider and bike is supported equa
kozerog [31]

Answer:

A = 4.76 x 10⁻⁴ m²

Explanation:

given,                                  

weight of the person = 625 N

weight of the bike = 98 N        

Pressure on each Tyre = 7.60 x 10⁵ Pa

Area of contact on each Tyre = ?          

total weight of the system = 625 + 98

                                             = 723 N

Let F be the force on both the Tyre

F + F = W                                    

2 F  = 723                                    

F = 361.5 N                                

F = P A                                            

A = \dfrac{F}{P}                          

A = \dfrac{361.5}{7.60 \times 10^5}

A = 4.76 x 10⁻⁴ m²

7 0
2 years ago
A charged cell phone has chemical energy stored in its battery. As you use your phone, the amount of chemical energy in the batt
Lunna [17]

Answer:

Because the chemical energy is converted to electrical enegy in the cell phone

Explanation:

This set up is not a voilation of the first law of thermodynamics because the chemical energy is not lost, it is only being transformed into electrical energy.

According to the first law of thermodynamics "energy is neither created nor destroyed but transformed from one form to another".

  • In a charged cell phone, the chemical energy is being transformed to electrical energy as you use it.
  • A phone cannot directly be powered with chemical energy.
  • The energy transformation to electrical energy makes it possible to use the phone.
  • In this process no energy is lost nor created. But simply, energy is transformed.
6 0
2 years ago
An organ pipe is made to play a low note at 27.5 Hz, the same as the lowest note on a piano. Assuming a sound speed of 343 m/s,
timama [110]

Answer:

The length of open-open pipe needed is 6.23 m

The length of open-close  pipe needed is 3.11 m

Explanation:

Fundamental frequency for standing wave mode of  an open- open pipe is given by

f=\frac{v}{2L}

where v is the velocity and L is the length

The length of open-open pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

Fundamental frequency for standing wave mode of  an open- close pipe is given by

f=\frac{v}{2L}

The length of open-close pipe needed is

L=\frac{v}{2f} \\L=\frac{343}{2\times 27.5} \\L=6.23 m

7 0
2 years ago
Two weights are connected by a very light cord that passes over an 80.0Nfrictionless pulley of radius 0.300m. The pulley is a so
Citrus2011 [14]

Answer:

The force does the ceiling exert on the hook is 269.59 N

Explanation:

Applying the second Newton law:

F = m*a

From the attached diagram, the net force in object 1 is:

m_{1} a=T_{1} -W_{1}

In object 2:

m_{2} a=W_{2} -T_{2}

Adding the two equations:

m_{2} a+m_{1} a=T_{1} -W_{1} +W_{2} -T_{2} \\m_{1} =\frac{W_{1} }{g} \\m_{2} =\frac{W_{2} }{g} \\Replacing\\T_{2}-T_{1}=W_{2}   -W_{1} -(\frac{W_{1} }{g} +\frac{W_{2} }{g} )a  (eq. 1)

The torque:

\tau =I\alpha

Where

I = moment of inertia

α = angular acceleration

If the linear acceleration is

a=r\alpha \\\alpha =\frac{a}{r} \\I=\frac{1}{2} mr^{2} \\\tau =\frac{mra}{2}

Torque due the tension is equal:

\tau =r(T_{2} -T_{1} )

Substituting torque, mass, in equation 1, the expression respect the acceleration is:

a=\frac{g*(W_{2}-W_{1})}{W_{1}+W_{2} +\frac{W}{2} }

Where

W₁ = 75 N

W₂ = 125 N

W = 80 N

a=\frac{9.8*(125-75)}{75+125+\frac{80}{2} } =2.04m/s^{2}

The net force is:

F_{n} =F-W-T_{1} -T_{2}\\0=F-W-W_{1} (\frac{a}{g} +1)-W_{2} (1-\frac{a}{g})\\F=W+W_{1} +W_{2} +\frac{a}{g} (W_{1} -W_{2} )\\F=80+75+125+\frac{2.04}{9.8} (75-125)\\F=269.59N

4 0
2 years ago
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