Answer:
t = 0.33h = 1200s
x = 18.33 km
Explanation:
If the origin of coordinates is at the second car, you can write the following equations for both cars:
car 1:
(1)
xo = 10 km
v1 = 55km/h
car 2:
(2)
v2 = 85km/h
For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:
The position in which both cars coincides is:
Answer:
a) a = -g = 9.8 m/s² , b) a = 0 m/s² and c) t1 = 0.0213 s
Explanation:
a) At the moment the marble is released its velocity is zero, so it has no resistance force, the only force acting is its weight, so the acceleration is the acceleration of gravity
a = -g = 9.8 m / s²
b) When the marble goes its terminal velocity all forces have been equalized, therefore, the sum of them is zero and consequently if acceleration is also zero
a = 0 m / s²
c) We have to assume a specific type of resistive force, for liquid in general the resistive force is proportional to the speed of the body.
The expression of this situation is
v = mg / b (1 - )
For a very long time the exponential is zero, so the terminal velocity is
= mg / b
b = mg /
b = 5 10-3 9.8 / 0.3
b = 0.163
We already have all the data to calculate the time for v = ½
½ =
(1 -
)
½ = 1- e (- 0.163 t1 / 5 10-3)
e (-32.6 t1) = 1-0.5 (by ln())
-32.6 t1 = ln 0.5
t1 = -1 / 32.6 (-0.693)
t1 = 0.0213 s
Answer:
Option (c) will be correct answer that is it will go 1.6 m
Explanation:
We have given that conveyor has the velocity u = 3.1 m/sec
Mass of the robot = 10 kg
static friction coefficient = 0.5 and kinetic friction coefficient = 0.3
Acceleration due to gravity g = 9.8
Acceleration a = kinetic friction coefficient ×g = 0.3×9.8 = 2.94
Now according to third equation of motion
Finally velocity of the conveyor will be zero
So
s = 1.6 m
So option (c) is correct option