Answer:
temperature on left side is 1.48 times the temperature on right
Explanation:
GIVEN DATA:
T1 = 525 K
T2 = 275 K
We know that
n and v remain same at both side. so we have
..............1
let final pressure is P and temp
..................2
similarly
.............3
divide 2 equation by 3rd equation
thus, temperature on left side is 1.48 times the temperature on right
Answer:
0.0367
Explanation:
The loss in kinetic energy results into work done by friction.
Since kinetic energy is given by
KE=0.5mv^{2}
Work done by friction is given as
W= umgd
Where m is the mass of suitacase, v is velocity of the suitcase, g is acceleration due to gravity, d is perpendicular distance where force is applied and u is coefficient of kinetic friction.
Making u the subject of the formula then we deduce that
Substituting v with 1.2 m/s, d with 2m and taking g as 9.81 m/s2 then
Therefore, the coefficient of kinetic friction is approximately 0.0367
Answer:
Answer
The Final Quality of teh R-134a in the container is 0.5056
The Total Heat transfer is
Explanation:
Explanation is in the following attachments
