Answer:
35°C
Explanation:
q = mCΔT
2130 J = (0.200 kg) (710 J/kg/°C) (T − 20.0°C)
T = 35°C
Answer:
number of electrons = 2.18*10^18 e
Explanation:
In order to calculate the number of electrons that move trough the second wire, you take into account one of the Kirchoff's laws. All the current that goes inside the junction, has to go out the junction.
Then, if you assume that the current of the wire 1 and 3 go inside the junction, then, all this current have to go out trough the second junction:
(1)
i1 = 0.40 A
i2 = 0.75 A
you solve the equation i3 from the equation (1):
Next, you take into account that 1A = 1C/s = 6.24*10^18
Then, you have:
The number of electrons that trough the wire 3 is 2.18*10^18 e/s
2NO2 means that there is 2 oxygen atoms and one nitrogen with two sets of that. So its the third one
Answer:
A
Explanation:
Solution:-
- According to the law of relativity the relative speed between two moving objects is inversely proportional to the the time taken.
- Ignoring Doppler Effect.
- So if the relative speeds of two objects in motion i.e ( swing and spaceship) are positive then the time frame of reference for both object relative to other other decreases. So in other words if spaceship approaches the swing i.e relative velocity is positive then the time period of oscillation observed would be less than actual i.e less than 4 seconds.
- Similarly, if spaceship moves away from the swing i.e relative velocity is negative then the time period of oscillation observed would be more than actual i.e more than 4 seconds.
