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densk [106]
1 year ago
6

A basketball with mass of 0.8 kg is moving to the right with velocity 6 m/s and hits a volleyball with mass of 0.6 kg that stays

at rest. If the volleyball moves to the right with velocity 4 m/s after collision, what’s the final velocity of the basketball?
Physics
1 answer:
IceJOKER [234]1 year ago
4 0

Answer:

26.67 m/s

Explanation:

From the law of conservation of linear momentum, the initial sum of momentum equals the final sum.

p=mv where p is momentum, m is the mass of object and v is the speed of the object

Initial momentum

The initial momentum will be that of basketball and volleyball, Since basketball is initially at rest, its initial velocity is zero

p_i= m_bv_b+m_vv_v=8*6+0.6*0=48 Kg.m/s

Final momentum

p_f= m_bv_b+m_vv_v=8*4+0.6*v_v=32+0.6v Kg.m/s\\32+0.6v_v=48\\0.6v=16\\v_v=16/0.6=26.66666667\approx 26.67 m/s

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dalvyx [7]

Answer:

at the highest point of the path the acceleration of ball is same as acceleration due to gravity

Explanation:

At the highest point of the path of the ball the speed of the ball becomes zero as the acceleration due to gravity will decelerate the motion of ball due to which the speed of ball will keep on decreasing and finally it comes to rest

So here we will say that at the highest point of the path the speed of the ball comes to zero

now by the force diagram we can say that net force on the ball due to gravity is given by

F_g = mg

now the acceleration of ball is given as

a = \frac{F_g}{m}

a = \frac{mg}{m} = g

so at the highest point of the path the acceleration of ball is same as acceleration due to gravity

5 0
1 year ago
The sound source of a ship’s sonar system operates at a frequency of 22.0 kHz . The speed of sound in water (assumed to be at a
stepladder [879]

Answer:

147.45 Hz

\Delta f=f_{Lr}-f_{Se}

Explanation:

v = Speed of sound in water = 1482 m/s

v_w = Speed of whale = 4.95 m/s

The difference in frequency is given by

\Delta f=f\dfrac{v+v_w}{v-v_w}-f\dfrac{v}{v-v_w}\\\Rightarrow \Delta f=f_{Lr}-f_{Se}

Frequency of the wave in stationary condition

f_{Lr}=f\dfrac{v+v_w}{v-v_w}

Ship's frequency which is reflected back

f_{Se}=f\dfrac{v}{v-v_w}

f_{Se}=22\ kHz

\mathbf{\Delta f=f_{Lr}-f_{Se}}

\Delta f=f_{Lr}-f_{Se}\\\Rightarrow \Delta f=22\times \dfrac{1482+4.95}{1482-4.95}-22\\\Rightarrow \Delta f=0.14745\ kHz\\\Rightarrow \Delta f=147.45\ Hz

The difference in wavelength is 147.45 Hz

3 0
2 years ago
Which best describes what occurs when a body accelerates?
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when a net force acts on a body, it produces acceleration in the body in the direction of the net force
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The awnser is. 1728000 kilometers
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2 years ago
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Find the wavelength of the ultrasonic wave emitted by a bat if it has a frequency of 4.0 * 10^4 Hz.
morpeh [17]

Remark

You have to pick a velocity for an ultra sound wave. I'm going to take the sound velocity to be 331 m/s in air, because I'm assuming that is what is meant: it is the sound a bat would make once he emits the ultrasound to a microphone like device that receives it. The media through which that happens is air.

Givens

v = 331m/s

f = 4 *10^4 hz

Formula

velocity = wavelength * frequency

v = \lambda*f

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0.008275 =  \lambda

8.275*10^-3 =  \lambda

5 0
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