Answer: 9.08KW and 16.21KW
Explanation:
The convection over a flat surface with a length of 10 m and a width of 6m.
The mean temperature is (5oC + 12oC)/2 = 8.5oC.
Then find the following properties of air at this temperature from Table A-15:
k = 0.02428 W/m(oC, v= 1.413x10-5 m2/s, and Pr = 0.7340.
find the Reynolds number. Re= VL/v
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This means that the flow becomes turbulent over the plate and we can use the Nusselt number equation for combined laminar and turbulent flow.
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We then use this Nusselt number to find the heat transfer coefficient and the heat transfer.
Check the screen shot for the calculation
Ans
9.08 kW
Then if the wind velocity were doubled, the Re number would be doubled and we would repeat the calculations above, starting with this revised Reynolds number..
Ans
16.21 kW
Answer: 1798
Explanation:
Given that there is no dielectric material between the plates,
the permittivity of free space = 9 × 10^-12 f/m
The frequency F = 10 MHz
The ratio of conduction current JC to the displacement current Jd is also known as loss tangent.
Please find the attached file for the solution
Answer:
Explanation:
For the problem, we should have same reynolds number
ρvd/mu = constant
1000×1×10⁻³×0.3×10⁻³/1.002×10⁻³ = 1400×0.5×d/600
d = 25.66 cm
Answer:
<em>The number of moles of palladium and tantalum are 0.00037 mole and 0.0000404 mole respectively</em>
Explanation:
Number of mole = reacting mass/molar mass
n = R.m/m.m......................... Equation 1
Where n = number of moles, R.m = reacting mass, m.m = molar mass.
For palladium,
R.m = 0.039 g and m.m = 106.42 g/mol
Substituting theses values into equation 1
n = 0.039/106.42
n = 0.00037 mole
For tantalum,
R.m = 0.0073 and m.m = 180.9 g/mol
Substituting these values into equation 1
n = 0.0073/180.9
n = 0.0000404 mole
<em>Therefore the number of moles of palladium and tantalum are 0.00037 mole and 0.0000404 mole respectively</em>
Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m