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uysha [10]
2 years ago
7

Which of the following substances will show the smallest change in temperature when equal amounts of energy are absorbed?

Physics
2 answers:
SSSSS [86.1K]2 years ago
3 0
It would be water because if you freeze it than you will still be able to see it and if you boil it than you will be able to see it disappear.
IgorLugansk [536]2 years ago
3 0

The correct answer of this question is : Water

EXPLANATION :

Before going to answer this question, first we have to understand the specific heat capacity.

The amount of heat required to raise the temperature of one gram of substance through one degree celsius is known as the specific heat capacity.

Hence, more is the specific heat of the substance, more is the heat required to change its temperature.

As per the questions, same amount of heat is given to water,air, sand and concrete.

The specific heat of water is more as compared to sand and concrete.

The specific heat of air is of two types like specific heat at constant pressure and specific heat at constant volume. Both these values are temperature dependent. Normally, specific heat at constant volume is less than water.

Hence, water will show the smallest change in temperature.

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A shot-putter exerts a force of 0.142 kN on a shot, accelerating it to 22.75 m/s2. What is the mass of the shot?
Svetach [21]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Force and Power.

Since, according to the Newton's law,

Force = mass * Acceleration.

hence, here

Force = 142 N, accelration = 22.75 m/s2

hence, mass = 142/22.75

===> Mass = 6.24 Kg

hence the mass of the shot is 6.24 Kg

8 0
2 years ago
A boy on a bicycle approaches a brick wall as he sounds his horn at a frequency 400 hz. the sound he hears reflected back from t
Mashutka [201]
As the question is about changing in frequency of a wave for an observer who is moving relative to the wave source, the concept that should come to our minds is "Doppler's effect."

Now the general formula of the Doppler's effect is:
f = (\frac{g + v_{r}}{g + v_{s}})f_{o} -- (A)

Note: We do not need to worry about the signs, as everything is moving towards each other. If something/somebody were moving away, we would have the negative sign. However, in this problem it is not the issue.

Where,
g = Speed of sound = 340m/s.
v_{r} = Velocity of the receiver/observer relative to the medium = ?.
v_{s} = Velocity of the source with respect to medium = 0 m/s.
f_{o} =  Frequency emitted from source = 400 Hz.
f = Observed frequency = 408Hz.

Plug-in the above values in the equation (A), you would get:

408 = ( \frac{340 + v_{r}}{340 + 0})*400

\frac{408}{400} =  \frac{340 + v_{r}}{340}

Solving above would give you,
v_{r} = 6.8 m/s

The correct answer = 6.8m/s



7 0
2 years ago
Which best explains why infrared waves are ineffective for treating cancer ?
Natali5045456 [20]
If it is a multiple choice  question is C. Infrared waves do not carry enough energy to kill cancerous cells.
8 0
2 years ago
Read 2 more answers
A potential difference of 10.0 volts exists between two points, A and B, within an electric field. What is the
Viefleur [7K]

Answer:

1. 5.0 x 10^2 C

Explanation:

V=W/Q

10 = 2.0 x 10^-2/Q

Q = 2.0 x 10^-2/ 10

Q = 5.0 x 10^2 C

7 0
2 years ago
A figure skater rotating at 5.00 rad/s with arms extended has a moment of inertia of 2.25 kg·m2. If the arms are pulled in so t
Serggg [28]

a) 6.25 rad/s

The law of conservation of angular momentum states that the angular momentum must be conserved.

The angular momentum is given by:

L=I\omega

where

I is the moment of inertia

\omega is the angular speed

Since the angular momentum must be conserved, we can write

L_1 = L_2\\I_1 \omega_1 = I_2 \omega_2

where we have

I_1 = 2.25 kg m^2 is the initial moment of inertia

\omega_1 = 5.00 rad/s is the initial angular speed

I_2 = 2.25 kg m^2 is the final moment of inertia

\omega_2 is the final angular speed

Solving for \omega_2, we find

\omega_2 = \frac{I_1 \omega_1}{I_2}=\frac{(2.25 kg m^2)(5.00 rad/s)}{1.80 kg m^2}=6.25 rad/s

b) 28.1 J and 35.2 J

The rotational kinetic energy is given by

K=\frac{1}{2}I\omega^2

where

I is the moment of inertia

\omega is the angular speed

Applying the formula, we have:

- Initial kinetic energy:

K=\frac{1}{2}(2.25 kg m^2)(5.00 rad/s)^2=28.1 J

- Final kinetic energy:

K=\frac{1}{2}(1.80 kg m^2)(6.25 rad/s)^2=35.2 J

7 0
2 years ago
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