Fm=Fe and am>ae
Hopefully this helps
This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide. Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after. Subtract this from the the system total and you will have the momentum of the other object after the collision. Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.
Be careful with the velocities. They are vectors, so direction matters. Typically moving to the right is positive (+) and moving to the left is negative (-). It is not clear from your question which direction the objects are moving before and after the collision.
Answer:
2805 °C
Explanation:
If the gas in the tank behaves as ideal gas at the start and end of the process. We can use the following equation:
The key issue is identify the quantities (P,T, V, n) in the initial and final state, particularly the quantities that change.
In the initial situation the gas have an initial volume
, temperature
, and pressure
,.
And in the final situation the gas have different volume
and temeperature
, the same pressure
,, and the same number of moles
,.
We can write the gas ideal equation for each state:
and
, as the pressure are equals in both states we can write
solving for
(*)
We know
= 935 °C, and that the
(the complete volume of the tank) is the initial volume
plus the part initially without gas which has a volume twice the size of the initial volume (read in the statement: the other side has a volume twice the size of the part containing the gas). So the final volume 
Replacing in (*)
Assume the acceleration due to gravity is approximately 9.8 m/s^2
In 1 second, it will fall
s = ut + at^2/2
u = initial vertical velocity = 0
a = 9.8
t = 1
s is the distance it falls
= 9.8/2 = 4.9 m
But the parcel has a horizontal velocity of 1 m/s so it will travel 1 m horizontally in 1 second.
The answer would be
1 metre, 4.9 metres.
The first part of the question is 3,100 V.
The second part of the question is 200 V.