Question

The gravitational field strength at a distance R from the center of moon is gR. The satellite is moved to a new circular orbit that is 2R from the center of the moon. What is the gravitational field strength of the moon at this new distance?

Answer 1

Answer:

$g'=\frac{g__R}{4}$

Explanation:

Given:

• gravitational field strength of moon at a distance R from its center, $g__R$

• Distance of the satellite from the center of the moon, $h=2R$

Now as we know that the value of gravity of any heavenly body is at height h is given as:

$g'=g__{R}} \times \frac{R^2}{(2R)^2}$

$g'=\frac{g__R}{4}$

∴The gravitational field strength will become one-fourth of what it is at the surface of the moon.