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Tom [10]
2 years ago
8

A good quarterback can throw a football at 27 m/s (about 60 mph). If we assume that the ball is caught at the same height from w

hich it is thrown, and if we ignore air resistance, what is the maximum range in meters (which is approximately the same as the range in yards) of a pass at this speed? How long is the ball in the air?
Physics
1 answer:
bezimeni [28]2 years ago
8 0

Answer:

The ball was in air for 3.896 s

Explanation:

given,

g = 9.8 m/s², acceleration due to gravity,

If the launch angle is 45°, the horizontal range will be maximum.

The horizontal and vertical launch velocities are equal, and each is equal to

v_h  =  v cos θ

v_h  =  27 × cos 45°

         = 19.09 m/s.

The time to attain maximum height is one half of the time of flight.

v = u + at                     ∵ v = 0 (max. height)

19.09 - 9.8 t₁ = 0

t₁ = 1.948 s

The time of flight is twice of the maximum height time

2 t₁ = 3.896 s

The horizontal distance traveled is

D = v × t

D = 3.896×19.09

   = 74.375 m

The ball was in air for 3.896 s

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