The thermal energy is where the work of friction comes from. That is what stops it eventually. In this case a counter force of 10N is applied over the distance of 30.0m. The energy is given by Force*Distance. Here this is 300J. This friction work is the thermal energy.
Answer:
please read the answer below
Explanation:
The angular momentum is given by

By taking into account the angles between the vectors r and v in each case we obtain:
a)
v=(2,0)
r=(0,1)
angle = 90°

b)
r=(0,-1)
angle = 90°

c)
r=(1,0)
angle = 0°
r and v are parallel
L = 0kgm/s
d)
r=(-1,0)
angle = 180°
r and v are parallel
L = 0kgm/s
e)
r=(1,1)
angle = 45°

f)
r=(-1,1)
angle = 45°
the same as e):
L = 5kgm/s
g)
r=(-1,-1)
angle = 135°

h)
r=(1,-1)
angle = 135°
the same as g):
L = 5kgm/s
hope this helps!!
Answer:
= 85.89 ° C
Explanation:
The linear thermal expansion process is given by
ΔL = L α ΔT
For the three-dimensional case, the expression takes the form
ΔV = V β ΔT
Let's apply this equation to our case
ΔV / V = -0.507% = -0.507 10-2
ΔT = (ΔV / V) 1 /β
ΔT = -0.507 10⁻² 1 / 1.15 10⁻³
ΔT = -4.409
–T₀ = 4,409
= T₀ - 4,409
= 90.3-4409
= 85.89 ° C
Answer:
Explanation:
Total mass of cable m = 190 x .402 = 76.38 lb
moment of inertial due to this cable = m r²
= 76.38 x (14/12)²
= 103.96 lb ft²
moment of inertia of empty spoon
= mR² where R is radius of gyration
= 65 x (11 / 12 )²
= 54.61 lb ft²
Total moment of inertia I = 158.57 lb ft²
Net force applied = force applied - frictional force
= 33 - 15 = 18 lb
= 18 x 32 poundal
= 576 poundal
Torque applied = force x radius
= 576 x 14/12
= 672 unit
Angular acceleration = torque / total moment of inertia
= 672 / 158.57
= 4.238 radian / s²
We can solve this problem using the force equation.
Force = Mass * Acceleration
2kg * 4m/s = 8 N
The net force required to keep the object moving at this speed and in this direction is 8 N.