Answer:
The order is 2>4>3>1 (TE)
Explanation:
Look up attached file
Answer:
Explanation:
m = Mass of stick
L = Length of stick = 1 m
h = Center of mass of stick = 
g = Acceleration due to gravity
T = Time period = 0.85 s
Time period is given by
Moment of inertia is given by
The acceleration of gravity on this planet is
Answer:
option A
Explanation:
given,
depth of the sea level = 10 m
g = 10 m/s²
Pressure underwater = ?
we know,
P = ρ g h
where ρ is the density of water which is equal to 1000 kg/m³
h is the depth of sea level
P = ρ g h
P = 1000 x 10 x 10
P = 100000 Pa
P = 100 kPa
Hence, the correct answer is option A
Answer:
A) T1 = 566 k = 293°C
B) T2 = 1132 k = 859°C
Explanation:
A)
The average kinetic energy of the molecules of an ideal gas is givwn by the formula:
K.E = (3/2)KT
where,
K.E = Average Kinetic Energy
K = Boltzman Constant
T = Absolute Temperature
At 10°C:
K.E = K10
T = 10°C + 273 = 283 K
Therefore,
K10 = (3/2)(K)(283)
FOR TWICE VALUE OF K10:
T = T1
Therefore,
2 K10 = (3/2)(K)(T1)
using the value of K10:
2(3/2)(K)(283) = (3/2)(K)(T1)
<u>T1 = 566 k = 293°C</u>
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B)
The average kinetic energy of the molecules of an ideal gas is given by the formula:
K.E = (3/2)KT
but K.E is also given by:
K.E = (1/2)(m)(vrms)²
Therefore,
(3/2)KT = (1/2)(m)(vrms)²
vrms = √(3KT/m)
where,
vrms = Root Mean Square Velocity of Molecule
K = Boltzman Constant
T = Absolute Temperature
m = mass
At
T = 10°C + 273 = 283 K
vrms = √[3K(283)/m]
FOR TWICE VALUE OF vrms:
T = T2
Therefore,
2 vrms = √(3KT2/m)
using the value of vrms:
2√[3K(283)/m] = √(3KT2/m)
2√283 = √T2
Squaring on both sides:
(4)(283) = T2
<u>T2 = 1132 k = 859°C</u>
<span>Johannes Kepler
</span>Isaac Newton
<span>Scientists who contributed to discovering the universal law of gravitation are Isaac Newton and Johannes Kepler. While, historically speaking, the discovery of gravitation is given to Newton, he said that he based his work on the law of motion, discovered by Kepler. </span>
