Answer:
d = Δv(t2-t1)
Explanation:
Speed is defined as the change of displacement with respect to time. It is expressed as shown;
Speed = change in displacement/change in time
Δv = d/Δt
d = Δv*Δt
d = ΔvΔt
Δt = t2-t1
d = Δv(t2-t1)
Δv is the change in rate of speed
Δt = change in time
The correct expression for the displacement of the car during this motion is d = Δv(t2-t1)
Answer:
the new diameter of the third ring = 0.607 mm
Explanation:
Consider the radius of 
bright ring when air is in between the lens and the plate ;
Using the expression: 
for the radius of the bright ring since the liquid (water ) of the refractive index 'n' is now in between the lens and the plate;
where;
= number of fringe
λ = wavelength
R = radius
n = refractive index of water
Now ;
the radius r of the third bright ring when the air is in between lens and plate = 
The new radius of the third bright fringe is 
Calculating the new diameter ; we have:
d(3) = 2(r(3))
d(3) = 2(0.3035)
d = 0.607 mm
Thus, the new diameter of the third ring = 0.607 mm
Answer:
The magnitude of the velocity of the aircraft P relative to aircraft Q is zero
Explanation:
The velocity of the two aircraft, P & Q, v = 300 m/s
The angle of the direction between them, Ф = 90°
The magnitude of the velocity of aircraft P relative to aircraft Q is given by the formula
<em> V = v cos Ф
</em>
Substituting the values in the above equation
v = 300 x cos 90°
= 300 x 0
= 0
Since the aircraft are at right angles, the velocity of one aircraft relative to the other is zero.
