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elena-14-01-66 [18.8K]
2 years ago
6

Juan was wearing a bright red shirt in a very dark room. What color did his shirt appear to the people with him in the room? A)

black B) blue C) brown D) red
Physics
2 answers:
ikadub [295]2 years ago
8 0
It would appear black.   

Hope I helped.  
Paladinen [302]2 years ago
3 0

Answer:

A. Black

Explanation:

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A Styrofoam slab has thickness h and density ρs. When a swimmer of mass m is resting on it, the slab floats in fresh water with
sattari [20]
 <span>A = area of styrofoam 
M = mass of stryofoam = A*h*rho_s 
m = mass of swimmer 

Total mass = m + M = m + A*h*rho_s 
Downward force = g*(total mass) = g*[m + A*h*rho_s] 

The slab is completely submerged. 
Buoyant force = g*(mass of water displaced) = g*[A*h*rho_w] 

Equate these 
g*[m + A*h*rho_s] = g*[A*h*rho_w] 
m + A*h*rho_s = A*h*rho_w 
A*h*[rho_w - rho_s] = m 
A = m/[h*(rho_w - rho_s)]</span>
8 0
2 years ago
A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal compone
patriot [66]

If I have done my math correctly, your answer is 67.5

4 0
2 years ago
Read 2 more answers
A 12 kg box sliding on a horizontal floor has an initial speed of 4.0 m/s. The coefficient of friction bctwecn thc box and the f
Hitman42 [59]

Answer:

(D) 96 kg-m/s

Explanation:

Let's start off by first calculating the normal force between the box and the floor.

This will be:

Normal Force = 12 * 9.81 = 117.72 N

We can now use the friction equation to find the frictional force on the box when it is moving:

Frictional force = Coefficient of friction * Normal Force

Frictional force = 0.4 * 117.72 = 47.09 N

Finally, since we have the force on the box, we can find the acceleration:

F = Mass * Acceleration

47.09 = 12 * Acceleration

Acceleration = 3.92 m/s^2

Final speed after 2 seconds:

V=U+a*t

V = 4 +(-3.92)*(2)

V= -3.84 m/s

Since we know the initial and final speeds, we can calculate the change in momentum:

Change in momentum = Final Momentum - Initial Momentum

Change in momentum = 3.84*12-(-4)*12

Change in momentum = 94.08 kg*m/s

Thus we can see that option (D) is the closest answer.

6 0
2 years ago
A 2.0 kg block on a horizontal frictionless surface is attached to a spring whose force constant is 590 N/m. The block is pulled
SVETLANKA909090 [29]

Answer:

The  value is  v =  -0.04 \  m/s

Explanation:

From the question we are told that

   The  mass  of the block is  m  =  2.0 \ kg

   The  force constant  of the spring is  k  =  590 \ N/m

   The amplitude  is  A =  + 0.080

   The  time consider is  t =  0.10 \  s

Generally the angular velocity of this  block is mathematically represented as

      w =  \sqrt{\frac{k}{m} }

=>   w =  \sqrt{\frac{590}{2} }

=>   w = 17.18 \  rad/s

Given that the block undergoes simple harmonic motion the velocity is mathematically represented as  

         v  =  -A w sin (w* t )

=>       v  = -0.080 * 17.18 sin (17.18* 0.10 )

=>       v =  -0.04 \  m/s

7 0
2 years ago
Hope you can answer this: A Student Visits A Farm And Makes These Notes In Her Journal.
Strike441 [17]

Answer:

Common Sense

Explanation:

The chick has probably seen other chicks get caught by the Hawk and knows not to go near, or saw a giant bird flying straight towards it and used common sense to identify it as danger and run away. Although if this is for a test or a grade or something, please do not use the answer, it is most likely incorrect. This is honestly my best answer.

8 0
1 year ago
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